Python: Fetch first 10 results from a list

Question:

Is there a way we can fetch first 10 results from a list. Something like this maybe:

``````list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

list.fetch(10)
``````

?

Answers:

``````list[:10]
``````

will give you the first 10 elements of this list using slicing.

However, note, it’s best not to use `list` as a variable identifier as it’s already used by Python: list()

To find out more about these type of operations you might find this tutorial on lists helpful and the link @DarenThomas provided Explain Python's slice notation – thanks Daren)

Use the slicing operator:

``````list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
list[:10]
``````

check this

`````` list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

list[0:10]
``````

Outputs:

``````[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
``````

The itertools module has lots of great stuff in it. So if a standard slice (as used by Levon) does not do what you want, then try the `islice` function:

``````from itertools import islice
l = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
iterator = islice(l, 10)
for item in iterator:
print item
``````
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