Python: Fetch first 10 results from a list

Question

Is there a way we can fetch first 10 results from a list. Something like this maybe:

list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

list.fetch(10)

?

Asked By: Amyth

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Source

Answer 1

list[:10]

will give you the first 10 elements of this list using slicing.

However, note, it’s best not to use list as a variable identifier as it’s already used by Python: list()

To find out more about these type of operations you might find this tutorial on lists helpful and the link @DarenThomas provided Explain Python's slice notation – thanks Daren)

Answered By: Levon

Answer 2

Use the slicing operator:

list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
list[:10]

Answered By: ddk

Answer 3

check this

 list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

 list[0:10]

Outputs:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Answered By: user1409289

Answer 4

The itertools module has lots of great stuff in it. So if a standard slice (as used by Levon) does not do what you want, then try the islice function:

from itertools import islice
l = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
iterator = islice(l, 10)
for item in iterator:
    print item

Answered By: Spencer Rathbun

Python: Fetch first 10 results from a list

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