How to copy files?


How do I copy a file in Python?

Asked By: Matt



shutil has many methods you can use. One of which is:

import shutil

shutil.copyfile(src, dst)

# 2nd option
shutil.copy(src, dst)  # dst can be a folder; use shutil.copy2() to preserve timestamp
  • Copy the contents of the file named src to a file named dst. Both src and dst need to be the entire filename of the files, including path.
  • The destination location must be writable; otherwise, an IOError exception will be raised.
  • If dst already exists, it will be replaced.
  • Special files such as character or block devices and pipes cannot be copied with this function.
  • With copy, src and dst are path names given as strs.

Another shutil method to look at is shutil.copy2(). It’s similar but preserves more metadata (e.g. time stamps).

If you use os.path operations, use copy rather than copyfile. copyfile will only accept strings.

Answered By: Swati

Use the shutil module.

copyfile(src, dst)

Copy the contents of the file named src to a file named dst. The destination location must be writable; otherwise, an IOError exception will be raised. If dst already exists, it will be replaced. Special files such as character or block devices and pipes cannot be copied with this function. src and dst are path names given as strings.

Take a look at filesys for all the file and directory handling functions available in standard Python modules.

Answered By: Airsource Ltd

copy2(src,dst) is often more useful than copyfile(src,dst) because:

  • it allows dst to be a directory (instead of the complete target filename), in which case the basename of src is used for creating the new file;
  • it preserves the original modification and access info (mtime and atime) in the file metadata (however, this comes with a slight overhead).

Here is a short example:

import shutil
shutil.copy2('/src/dir/file.ext', '/dst/dir/newname.ext') # complete target filename given
shutil.copy2('/src/file.ext', '/dst/dir') # target filename is /dst/dir/file.ext
Answered By: unmounted

Copying a file is a relatively straightforward operation as shown by the examples below, but you should instead use the shutil stdlib module for that.

def copyfileobj_example(source, dest, buffer_size=1024*1024):
    Copy a file from source to dest. source and dest
    must be file-like objects, i.e. any object with a read or
    write method, like for example StringIO.
    while True:
        copy_buffer =
        if not copy_buffer:

If you want to copy by filename you could do something like this:

def copyfile_example(source, dest):
    # Beware, this example does not handle any edge cases!
    with open(source, 'rb') as src, open(dest, 'wb') as dst:
        copyfileobj_example(src, dst)
Answered By: pi.

Directory and File copy example – From Tim Golden’s Python Stuff:

import os
import shutil
import tempfile

filename1 = tempfile.mktemp (".txt")
open (filename1, "w").close ()
filename2 = filename1 + ".copy"
print filename1, "=>", filename2

shutil.copy (filename1, filename2)

if os.path.isfile (filename2): print "Success"

dirname1 = tempfile.mktemp (".dir")
os.mkdir (dirname1)
dirname2 = dirname1 + ".copy"
print dirname1, "=>", dirname2

shutil.copytree (dirname1, dirname2)

if os.path.isdir (dirname2): print "Success"
Answered By: Noam Manos

You could use os.system('cp nameoffilegeneratedbyprogram /otherdirectory/')

or as I did it,

os.system('cp '+ rawfile + ' rawdata.dat')

where rawfile is the name that I had generated inside the program.

This is a Linux only solution

Answered By: mark
Function Copies
Uses file object Destination
may be directory
shutil.copy No Yes No Yes
shutil.copyfile No No No No
shutil.copy2 Yes Yes No Yes
shutil.copyfileobj No No Yes No
Answered By: jezrael

For large files, what I did was read the file line by line and read each line into an array. Then, once the array reached a certain size, append it to a new file.

for line in open("file.txt", "r"):
    if len(list) == 1000000: 
        del list[:]
Answered By: rassa45

Use to copy the file

from subprocess import call
call("cp -p <file> <file>", shell=True)
Answered By: deepdive

You can use one of the copy functions from the shutil package:

Function              preserves     supports          accepts     copies other
                      permissions   directory dest.   file obj    metadata  
shutil.copy              ✔             ✔                 ☐           ☐
shutil.copy2             ✔             ✔                 ☐           ✔
shutil.copyfile          ☐             ☐                 ☐           ☐
shutil.copyfileobj       ☐             ☐                 ✔           ☐


import shutil
shutil.copy('/etc/hostname', '/var/tmp/testhostname')
Answered By: maxschlepzig

For small files and using only python built-ins, you can use the following one-liner:

with open(source, 'rb') as src, open(dest, 'wb') as dst: dst.write(

This is not optimal way for applications where the file is too large or when memory is critical, thus Swati’s answer should be preferred.

Answered By: fabda01

Firstly, I made an exhaustive cheatsheet of shutil methods for your reference.

shutil_methods =
 'exception': ['exception shutil.SameFileError',
                 'exception shutil.Error'],

Secondly, explain methods of copy in exmaples:

  1. shutil.copyfileobj(fsrc, fdst[, length]) manipulate opened objects
In [3]: src = '~/Documents/Head+First+SQL.pdf'
In [4]: dst = '~/desktop'
In [5]: shutil.copyfileobj(src, dst)
AttributeError: 'str' object has no attribute 'read'
#copy the file object
In [7]: with open(src, 'rb') as f1,open(os.path.join(dst,'test.pdf'), 'wb') as f2:
    ...:      shutil.copyfileobj(f1, f2)
In [8]: os.stat(os.path.join(dst,'test.pdf'))
Out[8]: os.stat_result(st_mode=33188, st_ino=8598319475, st_dev=16777220, st_nlink=1, st_uid=501, st_gid=20, st_size=13507926, st_atime=1516067347, st_mtime=1516067335, st_ctime=1516067345)
  1. shutil.copyfile(src, dst, *, follow_symlinks=True) Copy and rename
In [9]: shutil.copyfile(src, dst)
IsADirectoryError: [Errno 21] Is a directory: ~/desktop'
#so dst should be a filename instead of a directory name
  1. shutil.copy() Copy without preseving the metadata
In [10]: shutil.copy(src, dst)
Out[10]: ~/desktop/Head+First+SQL.pdf'
#check their metadata
In [25]: os.stat(src)
Out[25]: os.stat_result(st_mode=33188, st_ino=597749, st_dev=16777220, st_nlink=1, st_uid=501, st_gid=20, st_size=13507926, st_atime=1516066425, st_mtime=1493698739, st_ctime=1514871215)
In [26]: os.stat(os.path.join(dst, 'Head+First+SQL.pdf'))
Out[26]: os.stat_result(st_mode=33188, st_ino=8598313736, st_dev=16777220, st_nlink=1, st_uid=501, st_gid=20, st_size=13507926, st_atime=1516066427, st_mtime=1516066425, st_ctime=1516066425)
# st_atime,st_mtime,st_ctime changed
  1. shutil.copy2() Copy with preseving the metadata
In [30]: shutil.copy2(src, dst)
Out[30]: ~/desktop/Head+First+SQL.pdf'
In [31]: os.stat(src)
Out[31]: os.stat_result(st_mode=33188, st_ino=597749, st_dev=16777220, st_nlink=1, st_uid=501, st_gid=20, st_size=13507926, st_atime=1516067055, st_mtime=1493698739, st_ctime=1514871215)
In [32]: os.stat(os.path.join(dst, 'Head+First+SQL.pdf'))
Out[32]: os.stat_result(st_mode=33188, st_ino=8598313736, st_dev=16777220, st_nlink=1, st_uid=501, st_gid=20, st_size=13507926, st_atime=1516067063, st_mtime=1493698739, st_ctime=1516067055)
# Preseved st_mtime
  1. shutil.copytree()

Recursively copy an entire directory tree rooted at src, returning the destination directory

Answered By: AbstProcDo

In Python, you can copy the files using

import os
import shutil
import subprocess

1) Copying files using shutil module

shutil.copyfile signature

shutil.copyfile(src_file, dest_file, *, follow_symlinks=True)

# example    
shutil.copyfile('source.txt', 'destination.txt')

shutil.copy signature

shutil.copy(src_file, dest_file, *, follow_symlinks=True)

# example
shutil.copy('source.txt', 'destination.txt')

shutil.copy2 signature

shutil.copy2(src_file, dest_file, *, follow_symlinks=True)

# example
shutil.copy2('source.txt', 'destination.txt')  

shutil.copyfileobj signature

shutil.copyfileobj(src_file_object, dest_file_object[, length])

# example
file_src = 'source.txt'  
f_src = open(file_src, 'rb')

file_dest = 'destination.txt'  
f_dest = open(file_dest, 'wb')

shutil.copyfileobj(f_src, f_dest)  

2) Copying files using os module

os.popen signature

os.popen(cmd[, mode[, bufsize]])

# example
# In Unix/Linux
os.popen('cp source.txt destination.txt') 

# In Windows
os.popen('copy source.txt destination.txt')

os.system signature


# In Linux/Unix
os.system('cp source.txt destination.txt')  

# In Windows
os.system('copy source.txt destination.txt')

3) Copying files using subprocess module signature, *, stdin=None, stdout=None, stderr=None, shell=False)

# example (WARNING: setting `shell=True` might be a security-risk)
# In Linux/Unix
status ='cp source.txt destination.txt', shell=True) 

# In Windows
status ='copy source.txt destination.txt', shell=True)

subprocess.check_output signature

subprocess.check_output(args, *, stdin=None, stderr=None, shell=False, universal_newlines=False)

# example (WARNING: setting `shell=True` might be a security-risk)
# In Linux/Unix
status = subprocess.check_output('cp source.txt destination.txt', shell=True)

# In Windows
status = subprocess.check_output('copy source.txt destination.txt', shell=True)

Answered By: kmario23
open(destination, 'wb').write(open(source, 'rb').read())

Open the source file in read mode, and write to destination file in write mode.

Answered By: Sundeep471

As of Python 3.5 you can do the following for small files (ie: text files, small jpegs):

from pathlib import Path

source = Path('../path/to/my/file.txt')
destination = Path('../path/where/i/want/to/store/it.txt')

write_bytes will overwrite whatever was at the destination’s location

Answered By: Marc

Python provides in-built functions for easily copying files using the Operating System Shell utilities.

Following command is used to Copy File


Following command is used to Copy File with MetaData Information

Answered By: Savai Maheshwari

Here is a simple way to do it, without any module. It’s similar to this answer, but has the benefit to also work if it’s a big file that doesn’t fit in RAM:

with open('sourcefile', 'rb') as f, open('destfile', 'wb') as g:
    while True:
        block =*1024*1024)  # work by blocks of 16 MB
        if not block:  # end of file

Since we’re writing a new file, it does not preserve the modification time, etc.
We can then use os.utime for this if needed.

Answered By: Basj

Similar to the accepted answer, the following code block might come in handy if you also want to make sure to create any (non-existent) folders in the path to the destination.

from os import path, makedirs
from shutil import copyfile
makedirs(path.dirname(path.abspath(destination_path)), exist_ok=True)
copyfile(source_path, destination_path)

As the accepted answers notes, these lines will overwrite any file which exists at the destination path, so sometimes it might be useful to also add: if not path.exists(destination_path): before this code block.

Answered By: R J

In case you’ve come this far down. The answer is that you need the entire path and file name

import os

shutil.copy(os.path.join(old_dir, file), os.path.join(new_dir, file))
Answered By: Leonardo Wildt

shutil module offers some high-level operations on files. It supports file copying and removal.

Refer to the table below for your use case.

Function Utilize
File Object
Directory Dest.
Answered By: Raymond Toh

shutil.copy(src, dst, *, follow_symlinks=True)

Answered By: Al Baari

Here is answer utilizing " shutil.copyfileobj" and is highly efficient. I used it in a tool I created some time ago. I didn’t wrote this originally but tweaked it a little bit.

def copyFile(src, dst, buffer_size=10485760, perserveFileDate=True):
    Copies a file to a new location. Much faster performance than Apache Commons due to use of larger buffer
    @param src:    Source File
    @param dst:    Destination File (not file path)
    @param buffer_size:    Buffer size to use during copy
    @param perserveFileDate:    Preserve the original file date
    #    Check to make sure destination directory exists. If it doesn't create the directory
    dstParent, dstFileName = os.path.split(dst)
    #    Optimize the buffer for small files
    buffer_size = min(buffer_size,os.path.getsize(src))
    if(buffer_size == 0):
        buffer_size = 1024
    if shutil._samefile(src, dst):
        raise shutil.Error("`%s` and `%s` are the same file" % (src, dst))
    for fn in [src, dst]:
            st = os.stat(fn)
        except OSError:
            # File most likely does not exist
            # XXX What about other special files? (sockets, devices...)
            if shutil.stat.S_ISFIFO(st.st_mode):
                raise shutil.SpecialFileError("`%s` is a named pipe" % fn)
    with open(src, 'rb') as fsrc:
        with open(dst, 'wb') as fdst:
            shutil.copyfileobj(fsrc, fdst, buffer_size)
        shutil.copystat(src, dst)
Answered By: Suleman Elahi

There are so many answers already, that I decided to add a different one.

You can use to create a hard link to a file:, dest)

This is not an independent clone, but if you plan to only read (not modify) the new file and its content must remain the same as the original, this will work well. It also has a benefit that if you want to check whether the copy already exists, you can compare the hard links (with os.stat) instead of their content.

Answered By: Yaroslav Nikitenko