Converting Epoch time into the datetime
Question:
I am getting a response from the rest is an Epoch time format like
start_time = 1234566
end_time = 1234578
I want to convert that epoch seconds in MySQL format time so that I could store the differences in my MySQL database.
I tried:
>>> import time
>>> time.gmtime(123456)
time.struct_time(tm_year=1970, tm_mon=1, tm_mday=2, tm_hour=10, tm_min=17, tm_sec=36, tm_wday=4, tm_yday=2, tm_isdst=0)
The above result is not what I am expecting. I want it be like
2012-09-12 21:00:00
Please suggest how can I achieve this?
Also,
Why I am getting TypeError: a float is required
for
>>> getbbb_class.end_time = 1347516459425
>>> mend = time.gmtime(getbbb_class.end_time).tm_hour
Traceback (most recent call last):
...
TypeError: a float is required
Answers:
Try this:
>>> import time
>>> time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(1347517119))
'2012-09-12 23:18:39'
Also in MySQL, you can FROM_UNIXTIME
like:
INSERT INTO tblname VALUES (FROM_UNIXTIME(1347517119))
For your 2nd question, it is probably because getbbb_class.end_time
is a string. You can convert it to numeric like: float(getbbb_class.end_time)
First a bit of info in epoch from man gmtime
The ctime(), gmtime() and localtime() functions all take an argument of data type time_t which represents calendar time. When inter-
preted as an absolute time value, it represents the number of seconds elapsed since 00:00:00 on January 1, 1970, Coordinated Universal
Time (UTC).
to understand how epoch should be.
>>> time.time()
1347517171.6514659
>>> time.gmtime(time.time())
(2012, 9, 13, 6, 19, 34, 3, 257, 0)
just ensure the arg you are passing to time.gmtime()
is integer.
To convert your time value (float or int) to a formatted string, use:
strftime('%Y-%m-%d %H:%M:%S', localtime(1347517370))
preceded by this import:
from time import strftime, localtime
This is what you need
In [1]: time.time()
Out[1]: 1347517739.44904
In [2]: time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(time.time()))
Out[2]: '2012-09-13 06:31:43'
Please input a float
instead of an int
and that other TypeError
should go away.
mend = time.gmtime(float(getbbb_class.end_time)).tm_hour
You can also use datetime
:
>>> import datetime
>>> datetime.datetime.fromtimestamp(1347517370).strftime('%c')
'2012-09-13 02:22:50'
#This adds 10 seconds from now.
from datetime import datetime
import commands
date_string_command="date +%s"
utc = commands.getoutput(date_string_command)
a_date=datetime.fromtimestamp(float(int(utc))).strftime('%Y-%m-%d %H:%M:%S')
print('a_date:'+a_date)
utc = int(utc)+10
b_date=datetime.fromtimestamp(float(utc)).strftime('%Y-%m-%d %H:%M:%S')
print('b_date:'+b_date)
This is a little more wordy but it comes from date command in unix.
>>> import datetime
>>> datetime.datetime.fromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
'2012-09-13 14:22:50' # Local time
To get UTC:
>>> datetime.datetime.utcfromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
'2012-09-13 06:22:50'
If you have epoch in milliseconds a possible solution is convert to seconds:
import time
time.ctime(milliseconds/1000)
For more time
functions: https://docs.python.org/3/library/time.html#functions
Sharing an answer to clearly distinguish UTC and local time conversions. Use import datetime
at the top before using the below methods.
Convert to datetime of local machine’s timezone
datetime.datetime.fromtimestamp(1347517370)
Convert to datetime of UTC timezone
datetime.datetime.utcfromtimestamp(1347517370)
For both the above methods, if you wish to return a formatted date string, use the following code block
datetime.datetime.fromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
datetime.datetime.utcfromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
I am getting a response from the rest is an Epoch time format like
start_time = 1234566
end_time = 1234578
I want to convert that epoch seconds in MySQL format time so that I could store the differences in my MySQL database.
I tried:
>>> import time
>>> time.gmtime(123456)
time.struct_time(tm_year=1970, tm_mon=1, tm_mday=2, tm_hour=10, tm_min=17, tm_sec=36, tm_wday=4, tm_yday=2, tm_isdst=0)
The above result is not what I am expecting. I want it be like
2012-09-12 21:00:00
Please suggest how can I achieve this?
Also,
Why I am getting TypeError: a float is required
for
>>> getbbb_class.end_time = 1347516459425
>>> mend = time.gmtime(getbbb_class.end_time).tm_hour
Traceback (most recent call last):
...
TypeError: a float is required
Try this:
>>> import time
>>> time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(1347517119))
'2012-09-12 23:18:39'
Also in MySQL, you can FROM_UNIXTIME
like:
INSERT INTO tblname VALUES (FROM_UNIXTIME(1347517119))
For your 2nd question, it is probably because getbbb_class.end_time
is a string. You can convert it to numeric like: float(getbbb_class.end_time)
First a bit of info in epoch from man gmtime
The ctime(), gmtime() and localtime() functions all take an argument of data type time_t which represents calendar time. When inter-
preted as an absolute time value, it represents the number of seconds elapsed since 00:00:00 on January 1, 1970, Coordinated Universal
Time (UTC).
to understand how epoch should be.
>>> time.time()
1347517171.6514659
>>> time.gmtime(time.time())
(2012, 9, 13, 6, 19, 34, 3, 257, 0)
just ensure the arg you are passing to time.gmtime()
is integer.
To convert your time value (float or int) to a formatted string, use:
strftime('%Y-%m-%d %H:%M:%S', localtime(1347517370))
preceded by this import:
from time import strftime, localtime
This is what you need
In [1]: time.time()
Out[1]: 1347517739.44904
In [2]: time.strftime("%Y-%m-%d %H:%M:%S", time.gmtime(time.time()))
Out[2]: '2012-09-13 06:31:43'
Please input a float
instead of an int
and that other TypeError
should go away.
mend = time.gmtime(float(getbbb_class.end_time)).tm_hour
You can also use datetime
:
>>> import datetime
>>> datetime.datetime.fromtimestamp(1347517370).strftime('%c')
'2012-09-13 02:22:50'
#This adds 10 seconds from now.
from datetime import datetime
import commands
date_string_command="date +%s"
utc = commands.getoutput(date_string_command)
a_date=datetime.fromtimestamp(float(int(utc))).strftime('%Y-%m-%d %H:%M:%S')
print('a_date:'+a_date)
utc = int(utc)+10
b_date=datetime.fromtimestamp(float(utc)).strftime('%Y-%m-%d %H:%M:%S')
print('b_date:'+b_date)
This is a little more wordy but it comes from date command in unix.
>>> import datetime
>>> datetime.datetime.fromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
'2012-09-13 14:22:50' # Local time
To get UTC:
>>> datetime.datetime.utcfromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
'2012-09-13 06:22:50'
If you have epoch in milliseconds a possible solution is convert to seconds:
import time
time.ctime(milliseconds/1000)
For more time
functions: https://docs.python.org/3/library/time.html#functions
Sharing an answer to clearly distinguish UTC and local time conversions. Use import datetime
at the top before using the below methods.
Convert to datetime of local machine’s timezone
datetime.datetime.fromtimestamp(1347517370)
Convert to datetime of UTC timezone
datetime.datetime.utcfromtimestamp(1347517370)
For both the above methods, if you wish to return a formatted date string, use the following code block
datetime.datetime.fromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')
datetime.datetime.utcfromtimestamp(1347517370).strftime('%Y-%m-%d %H:%M:%S')