Alphabet range in Python


How do I create a list of alphabet characters, without doing it manually like this?

['a', 'b', 'c', 'd', ..., 'z']
Asked By: Alexa Elis



>>> import string
>>> string.ascii_lowercase
>>> list(string.ascii_lowercase)
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

Alternatively, using range:

>>> list(map(chr, range(97, 123)))
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

Or equivalently:

>>> list(map(chr, range(ord('a'), ord('z')+1)))
['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z']

Other helpful string module features:

>>> help(string)
    ascii_letters = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'
    ascii_lowercase = 'abcdefghijklmnopqrstuvwxyz'
    digits = '0123456789'
    hexdigits = '0123456789abcdefABCDEF'
    octdigits = '01234567'
    printable = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ!"#$%&'()*+,-./:;<=>[email protected][\]^_`{|}~ tnrx0bx0c'
    punctuation = '!"#$%&'()*+,-./:;<=>[email protected][\]^_`{|}~'
    whitespace = ' tnrx0bx0c'
Answered By: jamylak

In Python 2.7 and 3 you can use this:

import string


As @Zaz says:
string.lowercase is deprecated and no longer works in Python 3 but string.ascii_lowercase works in both

Answered By: Trinh Nguyen
[chr(i) for i in range(ord('a'),ord('z')+1)]
Answered By: Bg1850

Here is a simple letter-range implementation:


def letter_range(start, stop="{", step=1):
    """Yield a range of lowercase letters.""" 
    for ord_ in range(ord(start.lower()), ord(stop.lower()), step):
        yield chr(ord_)


list(letter_range("a", "f"))
# ['a', 'b', 'c', 'd', 'e']

list(letter_range("a", "f", step=2))
# ['a', 'c', 'e']
Answered By: pylang

If you are looking to an equivalent of letters[1:10] from R, you can use:

import string
Answered By: Qaswed

Print the Upper and Lower case alphabets in python using a built-in range function

def upperCaseAlphabets():
    print("Upper Case Alphabets")
    for i in range(65, 91):
        print(chr(i), end=" ")

def lowerCaseAlphabets():
    print("Lower Case Alphabets")
    for i in range(97, 123):
        print(chr(i), end=" ")

Answered By: Lakshmikandan

This is the easiest way I can figure out:

for i in range(97, 123):
    print("{:c}".format(i), end='')

So, 97 to 122 are the ASCII number equivalent to ‘a’ to and ‘z’. Notice the lowercase and the need to put 123, since it will not be included).

In print function make sure to set the {:c} (character) format, and, in this case, we want it to print it all together not even letting a new line at the end, so end=''would do the job.

The result is this:

Answered By: RicarHincapie

Here is how I implemented my custom function for letters range generation based on string.ascii_letters:

from string import ascii_letters

def range_alpha(start_letter, end_letter):
  return ascii_letters[
    ascii_letters.index(start_letter):ascii_letters.index(end_letter) + 1

print(range_alpha('a', 'z'))
print(range_alpha('A', 'Z'))
print(range_alpha('a', 'Z'))
Answered By: Martin Tovmassian
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