I would like to get just the folder path from the full path to a file.
T:DataDBDesignDBDesign_93_v141b.mdb and I would like to get just
T:DataDBDesign (excluding the
I have tried something like this:
existGDBPath = r'T:DataDBDesignDBDesign_93_v141b.mdb' wkspFldr = str(existGDBPath.split('\')[0:-1]) print wkspFldr
but it gave me a result like this:
['T:', 'Data', 'DBDesign']
which is not the result that I require (being
Any ideas on how I can get the path to my file?
The built-in submodule os.path has a function for that very task.
import os os.path.dirname('T:DataDBDesignDBDesign_93_v141b.mdb')
WITH PATHLIB MODULE (UPDATED ANSWER)
One should consider using pathlib for new development. It is in the stdlib for Python3.4, but available on PyPI for earlier versions. This library provides a more object-orented method to manipulate paths
<opinion> and is much easier read and program with
>>> import pathlib >>> existGDBPath = pathlib.Path(r'T:DataDBDesignDBDesign_93_v141b.mdb') >>> wkspFldr = existGDBPath.parent >>> print wkspFldr Path('T:DataDBDesign')
WITH OS MODULE
Use the os.path module:
>>> import os >>> existGDBPath = r'T:DataDBDesignDBDesign_93_v141b.mdb' >>> wkspFldr = os.path.dirname(existGDBPath) >>> print wkspFldr 'T:DataDBDesign'
You can go ahead and assume that if you need to do some sort of filename manipulation it’s already been implemented in
os.path. If not, you’ll still probably need to use this module as the building block.
You were almost there with your use of the
split function. You just needed to join the strings, like follows.
>>> import os >>> '\'.join(existGDBPath.split('\')[0:-1]) 'T:\Data\DBDesign'
Although, I would recommend using the
os.path.dirname function to do this, you just need to pass the string, and it’ll do the work for you. Since, you seem to be on windows, consider using the
abspath function too. An example:
>>> import os >>> os.path.dirname(os.path.abspath(existGDBPath)) 'T:\Data\DBDesign'
If you want both the file name and the directory path after being split, you can use the
os.path.split function which returns a tuple, as follows.
>>> import os >>> os.path.split(os.path.abspath(existGDBPath)) ('T:\Data\DBDesign', 'DBDesign_93_v141b.mdb')
Here is the code:
import os existGDBPath = r'T:DataDBDesignDBDesign_93_v141b.mdb' wkspFldr = os.path.dirname(existGDBPath) print wkspFldr # T:DataDBDesign
Here is my little utility helper for splitting paths int file, path tokens:
import os # usage: file, path = splitPath(s) def splitPath(s): f = os.path.basename(s) p = s[:-(len(f))-1] return f, p
Anyone trying to do this in the ESRI GIS Table field calculator interface can do this with the Python parser:
I use this to change the current working directory to a folder;
from os import chdir from os.path import realpath from os.path import dirname chdir(realpath(dirname(argv)))