python selenium click on button


I am quite new to python selenium and I am trying to click on a button which has the following html structure:

<div class="b_div">

    <div class="button c_button s_button" onclick="submitForm('mTF')">
        <input class="very_small" type="button"></input>
        <div class="s_image"></div>

    <div class="button c_button s_button" onclick="submitForm('rMTF')" style="margin-bottom: 30px;">
        <input class="v_small" type="button"></input>


I would like to be able to click both the Search and Reset buttons above (obviously individually).

I have tried a couple of things, for example:

driver.find_element_by_css_selector('.button .c_button .s_button').click()





but, I seem to always end up with NoSuchElementException, for example:

selenium.common.exceptions.NoSuchElementException: Message: u'Unable to locate element: {"method":"name","selector":"s_image"}' ;

I am wondering if I can somehow use the onclick attributes of the HTML to make selenium click?

Any thoughts which can point me in the right direction would be great.

Asked By: AJW



Remove space between classes in css selector:

driver.find_element_by_css_selector('.button .c_button .s_button').click()
#                                           ^         ^


Answered By: falsetru

try this:

download firefox, add the plugin “firebug” and “firepath”; after install them go to your webpage, start firebug and find the xpath of the element, it unique in the page so you can’t make any mistake.

See picture:

browser.find_element_by_xpath('just copy and paste the Xpath').click()

Answered By: Carlo 1585

I had the same problem using Phantomjs as browser, so I solved in the following way:


Essentially I have added the name of the DIV tag into the quote.

Answered By: CosimoCD

The following debugging process helped me solve a similar issue.

with open("output_init.txt", "w") as text_file:

xpath1 = "the xpath of the link you want to click on"
destination_page_link = driver.find_element_by_xpath(xpath1)

with open("output_dest.txt", "w") as text_file:

You should then have two textfiles with the initial page you were on (‘output_init.txt’) and the page you were forwarded to after clicking the button (‘output_dest.txt’). If they’re the same, then yup, your code did not work. If they aren’t, then your code worked, but you have another issue.
The issue for me seemed to be that the necessary javascript that transformed the content to produce my hook was not yet executed.

Your options as I see it:

  1. Have the driver execute the javascript and then call your find
    element code. Look for more detailed answers on this on
    stackoverflow, as I didn’t follow this approach.
  2. Just find a comparable hook on the ‘output_dest.txt’ that will produce the same result, which is what I did.
  3. Try waiting a bit before clicking anything:

xpath2 = “your xpath that you are going to click on”

WebDriverWait(driver, timeout=5).until(lambda x:

The xpath approach isn’t necessarily better, I just prefer it, you can also use your selector approach.

Answered By: Tanel

For python, use the

from selenium.webdriver import ActionChains


Answered By: AshishGalagali

open a website and click on button to download the file and even i want to close the pop up if it comes using python selenium

from selenium import webdriver
from import By
from import WebDriverWait
from import expected_conditions as EC
import time
from import Options 

#For Mac - If you use windows change the chromedriver location
chrome_path = '/usr/local/bin/chromedriver'
driver = webdriver.Chrome(chrome_path)

chrome_options = webdriver.ChromeOptions()


# driver.get("")
# tabName = driver.find_element_by_link_text("Investment Adviser Data")


# report1 = driver.find_element_by_xpath("//div[@class='compilation-container ng-scope layout-column flex']//div[1]//div[1]//div[1]//div[2]//button[1]")

report1 = driver.find_element_by_xpath("//button[@analytics-label='IAPD - SEC Investment Adviser Report (GZIP)']")

# print(report1)


Answered By: Rajiv Singh

I had the same problem and with Firefox, I got button element with the following steps:

  • right click button of interest and select "Inspect Accessibility Properties"
  • this opens the inspector. Right click the highlighted line and click "Print to JSON"
  • this opens a new tab. Look for nodeCssSelector and copy the value

This allowed me to accept cookies of the website Yahoo by using.

url = ""
driver = Firefox(executable_path="geckodriver.exe")

I tested this further and it allowed me to accept individual cookies with ease. Simply repeat the mentioned steps from before to get the button names.

url = ""
driver = Firefox(executable_path="geckodriver.exe")
driver.find_element_by_css_selector(".firstPartyAds > div:nth-child(2) > label:nth-child(1)").click()
driver.find_element_by_css_selector(".preciseGeolocation > div:nth-child(2) > label:nth-child(1)").click()

Another method is to

  • right click button of interest and select "Inspect"
  • right click the highlighted line and click "Copy -> CSS Selector" or whatever you need (there are multiple options, including XPath)

However, I think the second method may include whitespaces depending on what you copy, so you might need to manually remove (some of) them. The first method seems to be more foolproof, but I don’t know if/how it works on other browsers than Firefox. The second method should work for all browsers.

Answered By: Tobias

Use This code To Click On Button

# finding the button using ID
button = driver.find_element_by_id(ID)

# clicking on the button

e = driver.find_element(By.XPATH, 's_image').click()

sometime it does not work!
you can try:

e = driver.find_element(By.XPATH, 's_image') driver.execute_script("arguments[0].click();", e)

Answered By: lam vu Nguyen