CSV file written with Python has blank lines between each row

Question:

import csv

with open('thefile.csv', 'rb') as f:
  data = list(csv.reader(f))
  import collections
  counter = collections.defaultdict(int)

  for row in data:
        counter[row[10]] += 1


with open('/pythonwork/thefile_subset11.csv', 'w') as outfile:
    writer = csv.writer(outfile)
    for row in data:
        if counter[row[10]] >= 504:
           writer.writerow(row)

This code reads thefile.csv, makes changes, and writes results to thefile_subset1.

However, when I open the resulting csv in Microsoft Excel, there is an extra blank line after each record!

Is there a way to make it not put an extra blank line?

Asked By: Alex Gordon

||

Answers:

Note: It seems this is not the preferred solution because of how the extra line was being added on a Windows system. As stated in the python document:

If csvfile is a file object, it must be opened with the ‘b’ flag on platforms where that makes a difference.

Windows is one such platform where that makes a difference. While changing the line terminator as I described below may have fixed the problem, the problem could be avoided altogether by opening the file in binary mode. One might say this solution is more “elegent”. “Fiddling” with the line terminator would have likely resulted in unportable code between systems in this case, where opening a file in binary mode on a unix system results in no effect. ie. it results in cross system compatible code.

From Python Docs:

On Windows, ‘b’ appended to the mode
opens the file in binary mode, so
there are also modes like ‘rb’, ‘wb’,
and ‘r+b’. Python on Windows makes a
distinction between text and binary
files; the end-of-line characters in
text files are automatically altered
slightly when data is read or written.
This behind-the-scenes modification to
file data is fine for ASCII text
files, but it’ll corrupt binary data
like that in JPEG or EXE files. Be
very careful to use binary mode when
reading and writing such files. On
Unix, it doesn’t hurt to append a ‘b’
to the mode, so you can use it
platform-independently for all binary
files.

Original:

As part of optional paramaters for the csv.writer if you are getting extra blank lines you may have to change the lineterminator (info here). Example below adapated from the python page csv docs. Change it from ‘n’ to whatever it should be. As this is just a stab in the dark at the problem this may or may not work, but it’s my best guess.

>>> import csv
>>> spamWriter = csv.writer(open('eggs.csv', 'w'), lineterminator='n')
>>> spamWriter.writerow(['Spam'] * 5 + ['Baked Beans'])
>>> spamWriter.writerow(['Spam', 'Lovely Spam', 'Wonderful Spam'])
Answered By: Derek Litz

The csv.writer module directly controls line endings and writes rn into the file directly. In Python 3 the file must be opened in untranslated text mode with the parameters 'w', newline='' (empty string) or it will write rrn on Windows, where the default text mode will translate each n into rn.

#!python3
with open('/pythonwork/thefile_subset11.csv', 'w', newline='') as outfile:
    writer = csv.writer(outfile)

In Python 2, use binary mode to open outfile with mode 'wb' instead of 'w' to prevent Windows newline translation. Python 2 also has problems with Unicode and requires other workarounds to write non-ASCII text. See the Python 2 link below and the UnicodeReader and UnicodeWriter examples at the end of the page if you have to deal with writing Unicode strings to CSVs on Python 2, or look into the 3rd party unicodecsv module:

#!python2
with open('/pythonwork/thefile_subset11.csv', 'wb') as outfile:
    writer = csv.writer(outfile)

Documentation Links

Answered By: Mark Tolonen

The simple answer is that csv files should always be opened in binary mode whether for input or output, as otherwise on Windows there are problems with the line ending. Specifically on output the csv module will write rn (the standard CSV row terminator) and then (in text mode) the runtime will replace the n by rn (the Windows standard line terminator) giving a result of rrn.

Fiddling with the lineterminator is NOT the solution.

Answered By: John Machin

Opening the file in binary mode “wb” will not work in Python 3+. Or rather, you’d have to convert your data to binary before writing it. That’s just a hassle.

Instead, you should keep it in text mode, but override the newline as empty. Like so:

with open('/pythonwork/thefile_subset11.csv', 'w', newline='') as outfile:
Answered By: David Maddox

I’m writing this answer w.r.t. to python 3, as I’ve initially got the same problem.

I was supposed to get data from arduino using PySerial, and write them in a .csv file. Each reading in my case ended with 'rn', so newline was always separating each line.

In my case, newline='' option didn’t work. Because it showed some error like :

with open('op.csv', 'a',newline=' ') as csv_file:

ValueError: illegal newline value: ''

So it seemed that they don’t accept omission of newline here.

Seeing one of the answers here only, I mentioned line terminator in the writer object, like,

writer = csv.writer(csv_file, delimiter=' ',lineterminator='r')

and that worked for me for skipping the extra newlines.

Answered By: Debanjan Dey

When using Python 3 the empty lines can be avoid by using the codecs module. As stated in the documentation, files are opened in binary mode so no change of the newline kwarg is necessary. I was running into the same issue recently and that worked for me:

with codecs.open( csv_file,  mode='w', encoding='utf-8') as out_csv:
     csv_out_file = csv.DictWriter(out_csv)
Answered By: JBa

Use the method defined below to write data to the CSV file.

open('outputFile.csv', 'a',newline='')

Just add an additional newline='' parameter inside the open method :

def writePhoneSpecsToCSV():
    rowData=["field1", "field2"]
    with open('outputFile.csv', 'a',newline='') as csv_file:
        writer = csv.writer(csv_file)
        writer.writerow(rowData)

This will write CSV rows without creating additional rows!

Answered By: Febin Mathew
with open(destPath+'\'+csvXML, 'a+') as csvFile:
    writer = csv.writer(csvFile, delimiter=';', lineterminator='r')
    writer.writerows(xmlList)

The “lineterminator=’r'” permit to pass to next row, without empty row between two.

Answered By: SheRa

Borrowing from this answer, it seems like the cleanest solution is to use io.TextIOWrapper. I managed to solve this problem for myself as follows:

from io import TextIOWrapper

...

with open(filename, 'wb') as csvfile, TextIOWrapper(csvfile, encoding='utf-8', newline='') as wrapper:
    csvwriter = csv.writer(wrapper)
    for data_row in data:
        csvwriter.writerow(data_row)

The above answer is not compatible with Python 2. To have compatibility, I suppose one would simply need to wrap all the writing logic in an if block:

if sys.version_info < (3,):
    # Python 2 way of handling CSVs
else:
    # The above logic
Answered By: phantom-99w

A lot of the other answers have become out of date in the ten years since the original question. For Python3, the answer is right in the documentation:

If csvfile is a file object, it should be opened with newline=''

The footnote explains in more detail:

If newline=” is not specified, newlines embedded inside quoted fields will not be interpreted correctly, and on platforms that use rn linendings on write an extra r will be added. It should always be safe to specify newline=”, since the csv module does its own (universal) newline handling.

Answered By: AustinDahl

I used writerow

def write_csv(writer, var1, var2, var3, var4):
    """
    write four variables into a csv file
    """
    writer.writerow([var1, var2, var3, var4])      
        
numbers=set([1,2,3,4,5,6,7,2,4,6,8,10,12,14,16])
rules = list(permutations(numbers, 4))
#print(rules)
selection=[]
with open("count.csv", 'w',newline='') as csvfile:
    writer = csv.writer(csvfile)

    for rule in rules:
        number1,number2,number3,number4=rule
        if ((number1+number2+number3+number4)%5==0):
            #print(rule)
            selection.append(rule)
            write_csv(writer,number1,number2,number3,number4)
Answered By: Golden Lion
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