Reading a csv with a timestamp column, with pandas

Question

When doing:

import pandas
x = pandas.read_csv('data.csv', parse_dates=True, index_col='DateTime', 
                                names=['DateTime', 'X'], header=None, sep=';')

with this data.csv file:

1449054136.83;15.31
1449054137.43;16.19
1449054138.04;19.22
1449054138.65;15.12
1449054139.25;13.12

(the 1st colum is a UNIX timestamp, i.e. seconds elapsed since 1/1/1970), I get this error when resampling the data every 15 second with x.resample('15S'):

TypeError: Only valid with DatetimeIndex, TimedeltaIndex or PeriodIndex

It’s like the “datetime” information has not been parsed:

                 X
DateTime      
1.449054e+09  15.31                
1.449054e+09  16.19
...

How to import a .CSV with date stored as timestamp with pandas module?

Then once I will be able to import the CSV, how to access to the lines for which date > 2015-12-02 12:02:18 ?

Asked By: Basj

||

Source

Answer 1

You can parse the date yourself:

import time
import pandas as pd

def date_parser(string_list):
    return [time.ctime(float(x)) for x in string_list]

df = pd.read_csv('data.csv', parse_dates=[0],  sep=';', 
                 date_parser=date_parser, 
                 index_col='DateTime', 
                 names=['DateTime', 'X'], header=None)

The result:

>>> df
                        X
DateTime                  
2015-12-02 12:02:16  15.31
2015-12-02 12:02:17  16.19
2015-12-02 12:02:18  19.22
2015-12-02 12:02:18  15.12
2015-12-02 12:02:19  13.12

Answered By: Mike Müller

Answer 2

My solution was similar to Mike’s:

import pandas
import datetime
def dateparse (time_in_secs):    
    return datetime.datetime.fromtimestamp(float(time_in_secs))

x = pandas.read_csv('data.csv',delimiter=';', parse_dates=True,date_parser=dateparse, index_col='DateTime', names=['DateTime', 'X'], header=None)

out = x.truncate(before=datetime.datetime(2015,12,2,12,2,18))

Answered By: Budo Zindovic

Answer 3

Use to_datetime and pass unit='s' to parse the units as unix timestamps, this will be much faster:

In [7]:
pd.to_datetime(df.index, unit='s')

Out[7]:
DatetimeIndex(['2015-12-02 11:02:16.830000', '2015-12-02 11:02:17.430000',
               '2015-12-02 11:02:18.040000', '2015-12-02 11:02:18.650000',
               '2015-12-02 11:02:19.250000'],
              dtype='datetime64[ns]', name=0, freq=None)

Timings:

In [9]:

import time
%%timeit
import time
def date_parser(string_list):
    return [time.ctime(float(x)) for x in string_list]

df = pd.read_csv(io.StringIO(t), parse_dates=[0],  sep=';', 
                 date_parser=date_parser, 
                 index_col='DateTime', 
                 names=['DateTime', 'X'], header=None)
100 loops, best of 3: 4.07 ms per loop

and

In [12]:
%%timeit
t="""1449054136.83;15.31
1449054137.43;16.19
1449054138.04;19.22
1449054138.65;15.12
1449054139.25;13.12"""
df = pd.read_csv(io.StringIO(t), header=None, sep=';', index_col=[0])
df.index = pd.to_datetime(df.index, unit='s')
100 loops, best of 3: 1.69 ms per loop

So using to_datetime is over 2x faster on this small dataset, I expect this to scale much better than the other methods

Answered By: EdChum

Answer 4

The simplest way to do this:

df = pd.read_csv(f, parse_dates=['datecolumn', 'datecolumn1'], infer_datetime_format=True)

Answered By: Vetri

Reading a csv with a timestamp column, with pandas

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