return value from python script to shell script

Question

I am new in Python. I am creating a Python script that returns a string "hello world." And I am creating a shell script. I am adding a call from the shell to a Python script.

i need to pass arguments from the shell to Python.
i need to print the value returned from Python in the shell script.

This is my code:

shellscript1.sh

#!/bin/bash
# script for testing
clear
echo "............script started............"
sleep 1
python python/pythonScript1.py
exit

pythonScript1.py

#!/usr/bin/python
import sys

print "Starting python script!"
try:
    sys.exit('helloWorld1') 
except:
     sys.exit('helloWorld2')

Asked By: Abdul Manaf

||

Source

Answer 1

Pass command line arguments to shell script to Python like this:

python script.py $1 $2 $3

Print the return code like this:

echo $?

Answered By: coffee-converter

Answer 2

You can’t return message as exit code, only numbers. In bash it can accessible via $?. Also you can use sys.argv to access code parameters:

import sys
if sys.argv[1]=='hi':
    print 'Salaam'
sys.exit(0)

in shell:

#!/bin/bash
# script for tesing
clear
echo "............script started............"
sleep 1
result=`python python/pythonScript1.py "hi"`
if [ "$result" == "Salaam" ]; then
    echo "script return correct response"
fi

Answered By: Ali Nikneshan

Answer 3

You can also use exit() without sys; one less thing to import. Here’s an example:

$ python
>>> exit(1)
$ echo $?
1

$ python
>>> exit(0)
$ echo $?
0

Answered By: Samuel

return value from python script to shell script

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