Accessing a variable within a function from another function? python

Question

How would it be possible to get the value of Accessme in the mainloop function?

def example():
    test=True
    while test:
       print("some stuff")
       if test2==True:
          Accessme = 400                   # Need to access this
          print("some stuff")
             if test3==True:
                print("some stuff")
                mainloop(x,y)
       elif test2==False:
          print("some stuff")

def mainloop(x,y):
   cheese = 1
   noise = []
   for something in somecodehere:
       print("some stuff") 
   output = some more code here
   print("some stuff",Accessme )          #Calling from here

This is the error i get:

> NameError: name 'Accessme' is not defined

Asked By: Jonathan Laliberte

||

Source

Answer 1

If you want access to Accessme to be global (that is, outside of any particular function), then you need to tell each function that this is the case:

global Accessme

Use of globals is usually in bad style. If you want to get information out of a function, it would be better return that information, just as getting information into a function is best done by a parameter.

Answered By: Scott Hunter

Answer 2

Your example code was messy to word with so I simplified enough so you understand the concept:

def example():
    test=True
    while test:
       Accessme = 400 #Assign the variable
       break
    return Accessme #This will return the variable. Accessme is local to the function example and nowhere else. 

def mainloop(x=0,y=0):
    cheese = 1
    noise = []
    print("some stuff",example() ) #You can grab the output from example by calling the function example, not Accessme.

mainloop()

I advise you read up on Scope. Your issue was Accessme is not in the scope of mainloop.

Answered By: abe

Accessing a variable within a function from another function? python

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