How can I write a `try`/`except` block that catches all exceptions?


How can I write a try/except block that catches all exceptions?

Asked By: user469652



    # this will catch any exception or error

It is worth mentioning this is not proper Python coding. This will catch also many errors you might not want to catch.

Answered By: Yuval Adam

You can but you probably shouldn’t:

    print("Caught it!")

However, this will also catch exceptions like KeyboardInterrupt and you usually don’t want that, do you? Unless you re-raise the exception right away – see the following example from the docs:

    f = open('myfile.txt')
    s = f.readline()
    i = int(s.strip())
except IOError as (errno, strerror):
    print("I/O error({0}): {1}".format(errno, strerror))
except ValueError:
    print("Could not convert data to an integer.")
    print("Unexpected error:", sys.exc_info()[0])
Answered By: Tim Pietzcker

Apart from a bare except: clause (which as others have said you shouldn’t use), you can simply catch Exception:

import traceback
import logging

except Exception as e:
    # Logs the error appropriately. 

You would normally only ever consider doing this at the outermost level of your code if for example you wanted to handle any otherwise uncaught exceptions before terminating.

The advantage of except Exception over the bare except is that there are a few exceptions that it wont catch, most obviously KeyboardInterrupt and SystemExit: if you caught and swallowed those then you could make it hard for anyone to exit your script.

Answered By: Duncan

Very simple example, similar to the one found here:

If you’re attempting to catch ALL exceptions, then put all your code within the “try:” statement, in place of ‘print “Performing an action which may throw an exception.”‘.

    print "Performing an action which may throw an exception."
except Exception, error:
    print "An exception was thrown!"
    print str(error)
    print "Everything looks great!"
    print "Finally is called directly after executing the try statement whether an exception is thrown or not."

In the above example, you’d see output in this order:

1) Performing an action which may throw an exception.

2) Finally is called directly after executing the try statement whether an exception is thrown or not.

3) “An exception was thrown!” or “Everything looks great!” depending on whether an exception was thrown.

Hope this helps!

Answered By: Joshua Burns

You can do this to handle general exceptions

    a = 2/0
except Exception as e:
    print e.__doc__
    print e.message
Answered By: vwvolodya

To catch all possible exceptions, catch BaseException. It’s on top of the Exception hierarchy:

Python 3:

Python 2.7:

except BaseException as error:
    print('An exception occurred: {}'.format(error))

But as other people mentioned, you would usually not need this, only for specific cases.

Answered By: gitaarik

I’ve just found out this little trick for testing if exception names in Python 2.7 . Sometimes i have handled specific exceptions in the code, so i needed a test to see if that name is within a list of handled exceptions.

    raise IndexError #as test error
except Exception as e:
    excepName = type(e).__name__ # returns the name of the exception
Answered By: Danilo

There are multiple ways to do this in particular with Python 3.0 and above

Approach 1

This is simple approach but not recommended because you would not know exactly which line of code is actually throwing the exception:

def bad_method():
        sqrt = 0**-1
    except Exception as e:


Approach 2

This approach is recommended because it provides more detail about each exception. It includes:

  • Line number for your code
  • File name
  • The actual error in more verbose way

The only drawback is tracback needs to be imported.

import traceback

def bad_method():
        sqrt = 0**-1
    except Exception:

Answered By: grepit

I am adding the bonus method that can catch the exception with full traceback which can help you to understand the error more.

Python 3

import traceback

    # your code goes here
except Exception as e:
Answered By: Tamil Selvan

First of all, there are exceptions that you want them to break your code (as when this error happens your code will not function anyways!) and exceptions you want to capture silently/smoothly. Try differentiating them. You may not want to capture all exceptions there are!

Second, instead of capturing everything, you could take the time and go through the logs of your process. Let’s say you are getting a different/third-party exception, for example from a cloud service provider like GCP. In the logs, you could find the exception you are getting. Then, you could do something like this:

from google.api_core.exceptions import ServiceUnavailable, RetryError

for i in range(10):
      print("do something")

   except ValueError:
      print("I know this might happen for now at times! skipping this and continuing with my loop"

   except ServiceUnavailable:
      print("our connection to a service (e.g. logging) of gcp has failed")
      print("initializing the cloud logger again and try continuing ...") 

   except RetryError:
      print("gcp connection retry failed. breaking the loop. try again later!)

For the rest (errors that might or might not happen), I am leaving room for my code to crash if I get an unexpected exception! This way I could understand what is going on and improve my code by capturing edge cases.

If you want this to never crash for some reason, for example if it is a code embedded in a remote hardware that you cannot easily access, you can add a generic exception catcher at the end:

except Exception as e:
   print(f"something went wrong! - {e}")

You can also take a look at Python 3 exception hierarchy here. The difference between Exception and BaseException is that, Exception will not catch SystemExit, KeyboardInterrupt, or GeneratorExit

Answered By: Hossein Kalbasi
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