A way to insert a value in an empty List in a specific index

Question

Is there a way to insert a specific value into a List into a specific index. List should be completely empty:

L = []
L.insert(2,177)
print(L)

L should give out the values of L [ , ,117].

Asked By: user9935508

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Source

Answer 1

iterables in Python must have objects inside. You can fill the list with None up to the place you want your actual value

l = [None for _ in range(200)]
l[2] = 2
l[177] = 177

None

The sole value of types.NoneType. None is frequently used to represent the absence of a value, as when default arguments are not passed to a function.

Answered By: CIsForCookies

Answer 2

That is not possible. Lists cannot have “holes”; every slot in the list must contain a value.

You have two options:

Fill the list with dummy values:

L = [None] * 3
L[2] = 177
# L: [None, None, 177]

Use a dict rather than a list:
```
L = {}
L[2] = 177
# L: {2: 177}
```
A dict is a mapping between arbitrary values, so it can handle “holes” with no problem.

Answered By: Aran-Fey

A way to insert a value in an empty List in a specific index

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