"between()" function with only right or left inclusive

Question

all I am trying to filter some dates with pandas.
I initially tried doing that with this code

bd = pd.DataFrame({'year': [2018, 2018], # billing data
                    'month': [9, 10],
                    'day': [14, 15]})
bd = pd.to_datetime(bd)
month1 = (df2.Date >= bd[0]) & (df.Date < bd[1])

I would get the error of TypeError: Cannot compare type ‘Timestamp’ with type ‘str’

However, when I did the between() function

bd = pd.DataFrame({'year': [2018, 2018],
                    'month': [9, 10],
                    'day': [14, 15]})
bd = pd.to_datetime(bd)
month1 = df2[df2['Date'].between(bd[0], bd[1])]

It worked, but it would include the 15th of October which I do not want. The between() function is useful, but I would like to now what alternatives I have if I only need one side inclusive, and the other exclusive. Thank you for the help.

Asked By: Luis Enriquez-Contreras

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Answer 1

The fix for between is simple. You subtract one day on the side which you want the ‘exclusive’. In your case, it is like this

a_day = pd.DateOffset(1)
month1 = df2[df2['Date'].between(bd[0], bd[1] - a_day)

Otherwise, if you really want totally control on the inclusiveness of sides, you need to use pd.IntervalArray or pd.IntervalIndex

Answered By: Andy L.

Answer 2

I think between also supports a parameter called inclusive.

month1 = df2[df2['Date'].between(bd[0], bd[1], inclusive='left')]

Answered By: Jenny

"between()" function with only right or left inclusive

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