Most efficient way to remove a string pattern of several keys based on a list of patterns and removing duplicate keys

Question

The objective is to create a clean dictionary key: values pair removing a pattern contained in a list.
i.e

pattern_list = ['_PATTERN1','_PATTERN2']
test_dictionary = {'x_PATTERN1': '1', 'y_PATTERN2': 'Okay...'}
#desired result
test_dictionary = {'x': '1', 'y': 'Okay...'}

Have done in the past dict comprehension using this pattern

{k.replace('.', '') : v.replace('.', '') for k, v in x.items()}

However, I wonder how can I use a list instead of a single string to avoid writing the same lines and code. Also, I wonder what is the best practice if there is any duplicated key:value pair.

Asked By: DonCharlie

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Source

Answer 1

how about a own function to clean keys?

pattern_list = ['_PATTERN1','_PATTERN2']
def clean_key(key):
    for pattern in pattern_list:
        key = key.replace(pattern, "")
    return key
{clean_key(k) :  v for k, v in x.items()}

Answered By: stefan

Most efficient way to remove a string pattern of several keys based on a list of patterns and removing duplicate keys

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