# Python How to break loop with 0

## Question:

I don’t understand why is not working on my code

```
def random_calculation(num):
return((num*77 + (90+2-9+3)))
while random_calculation:
num = int(input("Pleace enter number: "))
if num == "0":
break
else:
print(random_calculation(num))
```

Can you guide me what is wrong here, i really dont understand

## Answers:

so,when you start the loop it ask you what number you want to enter and then the code checks if the number is == to 0. IF the number is equal to 0: break the loop. IF the number is equal to any other number it prints the "random_calculation" function

You have several errors in your code:

You cannot do `while random_calculation`

like this. You need to call the function, but since inside the loop you are already checking for a break condition, use while True instead.

Also, you are converting the input to int, but then comparing agains the string "0" instead of the int 0

Here’s the corrected code:

```
def random_calculation(num):
# 90+2-9+3 is a bit strange, but not incorrect.
return((num*77 + (90+2-9+3)))
while True:
num = int(input("Please enter number: "))
if num == 0:
break
# you don't need an else, since the conditional would
# break if triggered, so you can save an indentation level
print(random_calculation(num))
```