How to convert my dictionary query to properly formatted string without getting garbage?


Assume this is my dictionary:

dc = { 0 : { "name" : "A", "value" : 4}, 1 : {"name" : "B", "value" : 5}, 2: {"name" : "C", "value" : 7}}

I need to transform all values from keys value into a string formatted like this:

(4, 5, 7)

Format is mandatory (this is some robotic automation) – series of integers, separated by , and surrounded by (). No other garbage.

Good examples:

(1, 5, 15, 37, 123, 56874)

Bad examples:

[4, 5, 7]
{4, 5, 7}
('4', '5', '7')

My naive approach was "lets iterate over all dictionary items, collect all "values" into tuple and then str it", but tuples cannot be modified. So I said "ok, collect to list, convert to tuple and then str":

res = list()
for item in dc.values():

I’m new to Python and I bet there is more elegant way of doing this, but it worked fine for multi-item and empty results. However, if my query returns only single item, then Python adds an extra empty item and it breaks the robotic client.


Is there way of not getting this empty extra without explicit checking if len(res)==1?

Actually, is there more robust and elegant way of cutting out all values into strictly formatted string as I need?

Asked By: Noname



You can use one line generator:

tuple(item['value'] for item in dc.values())
#(4, 5, 7)

If you just have 1 value you can add [0] at the end:

tuple(item['value'] for item in dc.values())[0]

Else you will get like:


If you have 1 value and you want string datatype then:

str(tuple(item['value'] for item in dc.values())[0])


You can try:

'(' + ', '.join(str(item['value']) for item in dc.values()) + ')'

for single value:


for multiple values:

#'(4, 5, 7)'
Answered By: God Is One
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