Match at the beggining OR after whitespace with square bracket, r'[^s]+word'
Question:
None these three matches
m = re.search(r'[^s]+ss', "aa ss")
m = re.search(r'[^s]+ss', "ss")
m = re.search(r'[^s]+ss', " ss")
But this matches
m = re.search(r'[s^]+ss', " ss")
What’s the usually way to match the word "ss" at the beginning or after one or more white-space in a string?
Answers:
If I understood it correctly, you can match on the start of the line or a whitespace using |:
(?:^|s)ss
(?: – start of non-capturing group
^|s – match on the beginning of the line or a whitespace
) – end of non-capturing groupss – match on literal ss
In your try:
[^s] will match exactly one character that is not a whitespace. [^...] makes the character group negated so that non of the characters in the group is allowed.[s^] will match exactly one character that is either a whitespace or a literal ^ (not the start of the string).
None these three matches
m = re.search(r'[^s]+ss', "aa ss")
m = re.search(r'[^s]+ss', "ss")
m = re.search(r'[^s]+ss', " ss")
But this matches
m = re.search(r'[s^]+ss', " ss")
What’s the usually way to match the word "ss" at the beginning or after one or more white-space in a string?
If I understood it correctly, you can match on the start of the line or a whitespace using |:
(?:^|s)ss
(?:– start of non-capturing group^|s– match on the beginning of the line or a whitespace
)– end of non-capturing groupss– match on literalss
In your try:
[^s]will match exactly one character that is not a whitespace.[^...]makes the character group negated so that non of the characters in the group is allowed.[s^]will match exactly one character that is either a whitespace or a literal^(not the start of the string).