cannot import name 'save_virtual_workbook' from 'openpyxl.writer.excel'
Question:
Is there an update to the library?
Before it worked perfectly, and today I updated and it no longer loads
I searched but I can’t find any other option
Answers:
I solve this issue by installing an older version 3.0.10
pip install openpyxl==3.0.10
Looks like the new recommendation from the developers is to use a temp-file:
https://openpyxl.readthedocs.io/en/3.1/tutorial.html?highlight=save#saving-as-a-stream
update: I ended up having to use this with modifications
from tempfile import NamedTemporaryFile
from openpyxl import Workbook
wb = Workbook()
with NamedTemporaryFile() as tmp:
tmp.close() # with statement opened tmp, close it so wb.save can open it
wb.save(tmp.name)
with open(tmp.name, 'rb') as f:
f.seek(0) # probably not needed anymore
new_file_object = f.read()
because the with
statement opens the file and then wb.save
(which expects a string
filename) attempts to open it, resulting in an Exception
The official recommendation does not work (as-is) on Windows + it uses the filesystem to save the workbook, even if only briefly.
Here a better method in my mind which is all in-memory:
with io.BytesIO() as buffer:
wb.save(buffer)
content = buffer.getvalue()
This works because the underlying ZipFile()
used here accepts a file-like object in addition to filename.
Is there an update to the library?
Before it worked perfectly, and today I updated and it no longer loads
I searched but I can’t find any other option
I solve this issue by installing an older version 3.0.10
pip install openpyxl==3.0.10
Looks like the new recommendation from the developers is to use a temp-file:
https://openpyxl.readthedocs.io/en/3.1/tutorial.html?highlight=save#saving-as-a-stream
update: I ended up having to use this with modifications
from tempfile import NamedTemporaryFile
from openpyxl import Workbook
wb = Workbook()
with NamedTemporaryFile() as tmp:
tmp.close() # with statement opened tmp, close it so wb.save can open it
wb.save(tmp.name)
with open(tmp.name, 'rb') as f:
f.seek(0) # probably not needed anymore
new_file_object = f.read()
because the with
statement opens the file and then wb.save
(which expects a string
filename) attempts to open it, resulting in an Exception
The official recommendation does not work (as-is) on Windows + it uses the filesystem to save the workbook, even if only briefly.
Here a better method in my mind which is all in-memory:
with io.BytesIO() as buffer:
wb.save(buffer)
content = buffer.getvalue()
This works because the underlying ZipFile()
used here accepts a file-like object in addition to filename.