How to substitute a list of words based on a list of tuples by preserving the same original order?
Question:
Given the following list of tokens:
a = ['heyyo', 'how', 'ale', 'yiou']
And a list of tuples:
b = [('yiou', 'you'), ('heyyo', 'hello')]
How can I replace the elements of the list a considering the elements of the list b? For example, the expected output would be:
['hello', 'how', 'ale', 'you']
This is due to list b has as a replacement:yiou for you and heyyo for hello. How to make the above replacement securing the same original order of list a?
Answers:
You can create a dict on b and then search each item of a in dct_b with dict.get(). If exist return value base key and if doesn’t exist return the item.
dct_b = dict(b)
res = [dct_b.get(item, item) for item in a]
print(res)
Output:
['hello', 'how', 'ale', 'you']
Too late, but at least short 🙂
res = [*map(dict(b).get, a, a)]
Given the following list of tokens:
a = ['heyyo', 'how', 'ale', 'yiou']
And a list of tuples:
b = [('yiou', 'you'), ('heyyo', 'hello')]
How can I replace the elements of the list a considering the elements of the list b? For example, the expected output would be:
['hello', 'how', 'ale', 'you']
This is due to list b has as a replacement:yiou for you and heyyo for hello. How to make the above replacement securing the same original order of list a?
You can create a dict on b and then search each item of a in dct_b with dict.get(). If exist return value base key and if doesn’t exist return the item.
dct_b = dict(b)
res = [dct_b.get(item, item) for item in a]
print(res)
Output:
['hello', 'how', 'ale', 'you']
Too late, but at least short 🙂
res = [*map(dict(b).get, a, a)]