GuildPrefix Command Confused

Question

        @bot.command()
        async def guildprefix(ctx, prefix):
            with open('prefixes.json', 'r') as f:
                prefixes = json.load(f)
            prefixes[str(ctx.guild.id)] = prefix
            with open('prefixes.json', 'w') as f:
                json.dump(prefixes, f, indent=4)
            await ctx.send(f'Prefix changed to: {prefix}')
            name=f'{prefix}BotBot'

def get_prefix(bot, message):
    with open('prefixes.json', 'r') as f:
        prefixes = json.load(f)
        prefixes[str(message.guild.id)] = '.'
        return prefixes[str(message.guild.id)]

It logs the prefix but won’t send when I do the prefix that I set it to

Asked By: notmeas

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Source

Answer 1

Your get_prefix method is setting the prefix to ".".

def get_prefix(bot, message):
    with open('prefixes.json', 'r') as f:
        prefixes = json.load(f)
    if str(message.guild.id) not in prefixes:
        # only set the default if it's not already in the file
        prefixes[str(message.guild.id)] = '.'
    return prefixes[str(message.guild.id)]

Now get_prefix will return the value in the file or "." if the guild ID isn’t already in the file.

Answered By: ESloman

GuildPrefix Command Confused

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