I don't understand why my code is looping when not supposed to

Question

This is very simple, and I may look dumb, I’m completely new to Python

In my function user(), I put a while loop to see that only 1 word is entered and no numbers. Its a vowel counter that accepts 1 word

I don’t understand why it keeps looping
I think continue means to skip all code ahead and go back to loop

Can someone please help me out

def user():
    global word
    while True:
        word = input(">")
        j = word.split(" ")
        if len(j) == 1:
            pass
        else:
            continue
        for _ in word:
            if _.isdigit():
                continue
            else:
                break
    return word

def vowel_check():
    global word
    word = word.lower()
    vowels = ["a","e","i","o","u"]
    vowel_count = 0
    for i in vowel:
        if i in vowels:
            vowel_count += 1
        else:
            pass
    print(vowel_count)

user()
vowel_check()

Asked By: Aryan Singh

||

Source

Answer 1

Both keywords, continue and break only apply to the "nearest" loop. Here you will fall out of the for-loop, but are still kept in the while-loop forever.
To solve this, you could instead of doing break in the while loop just return the found value here.

Answered By: syn

Answer 2

Rather than using global variables and various pass/continue/break structures you can simplify the whole process as follows:

VOWELS = set('aeiouAEIOU')

def user():
    while True:
        word = input('> ')
        if len(word.split()) == 1: # exactly one word
            if not any(c.isdigit() for c in word):
                return word

def vowel_check(s):
    return sum(c in VOWELS for c in s)

print(vowel_check(user()))

Answered By: Pingu

I don't understand why my code is looping when not supposed to

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