How do I get a function's output characters to be automatically counted in python?

Question

I am trying to print the number of characters that are present in the output my function gives. in this case I’m looking for 90 as "lowercase" 10 times is 90 characters. I’m not really sure what to try, please advise.

num=10
def func(word, add=5, freq=1):
    print(word*(freq+add))
test=func("lowercase", num)
print(test, num)
count(test)

When I tried to use the "count" function, I got the below error:

traceback (most recent call last):
File "c:UsersTzvi AryehDocumentspython programs#optional Parameters Tutorial #1.py", line 18, in
count(test)
^^^^^
NameError: name ‘count’ is not defined. Did you mean: ’round’?"

Asked By: Cortex8938

||

Source

Answer 1

The easiest solution is to modify your function so that it returns the output instead of printing it:

num=10
def func(word, add=5, freq=1):
    return word*(freq+add)

test=func("lowercase", num)
print(test, num)
print(len(test))

With your original code, func would directly print the output and then return None (meaning that test becomes None, which you can’t do anything with — when you try to print it after having called your function, you’ll just see None).

The above code returns the string, which is then assigned to test. The line print(test, num) prints:

lowercaselowercaselowercaselowercaselowercaselowercaselowercaselowercaselowercaselowercaselowercase 10

and the line print(len(test)) prints the len (length) of test:

Answered By: Samwise

How do I get a function's output characters to be automatically counted in python?

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