How do I convert seconds to hours, minutes and seconds?


I have a function that returns information in seconds, but I need to store that information in hours:minutes:seconds.

Is there an easy way to convert the seconds to this format in Python?

Asked By: Specto



By using the divmod() function, which does only a single division to produce both the quotient and the remainder, you can have the result very quickly with only two mathematical operations:

m, s = divmod(seconds, 60)
h, m = divmod(m, 60)

And then use string formatting to convert the result into your desired output:

print('{:d}:{:02d}:{:02d}'.format(h, m, s)) # Python 3
print(f'{h:d}:{m:02d}:{s:02d}') # Python 3.6+
Answered By: Brandon Rhodes

You can use datetime.timedelta function:

>>> import datetime
>>> str(datetime.timedelta(seconds=666))
Answered By: SilentGhost

I can hardly name that an easy way (at least I can’t remember the syntax), but it is possible to use time.strftime, which gives more control over formatting:

from time import strftime
from time import gmtime

strftime("%H:%M:%S", gmtime(666))

strftime("%H:%M:%S", gmtime(60*60*24))

gmtime is used to convert seconds to special tuple format that strftime() requires.

Note: Truncates after 23:59:59

Answered By: anatoly techtonik

Using datetime:

With the ':0>8' format:

from datetime import timedelta

# Result: '00:01:06'

# Result: '7 days, 17:12:57'

# Result: '2 days, 1:01:49'

Without the ':0>8' format:

# Result: '00:01:06'

# Result: '7 days, 17:12:57'

# Result: '2 days, 1:01:49'

Using time:

from time import gmtime
from time import strftime

# NOTE: The following resets if it goes over 23:59:59!

strftime("%H:%M:%S", gmtime(125))
# Result: '00:02:05'

strftime("%H:%M:%S", gmtime(60*60*24-1))
# Result: '23:59:59'

strftime("%H:%M:%S", gmtime(60*60*24))
# Result: '00:00:00'

strftime("%H:%M:%S", gmtime(666777))
# Result: '17:12:57'
# Wrong
Answered By: marcell

This is how I got it.

def sec2time(sec, n_msec=3):
    ''' Convert seconds to 'D days, HH:MM:SS.FFF' '''
    if hasattr(sec,'__len__'):
        return [sec2time(s) for s in sec]
    m, s = divmod(sec, 60)
    h, m = divmod(m, 60)
    d, h = divmod(h, 24)
    if n_msec > 0:
        pattern = '%%02d:%%02d:%%0%d.%df' % (n_msec+3, n_msec)
        pattern = r'%02d:%02d:%02d'
    if d == 0:
        return pattern % (h, m, s)
    return ('%d days, ' + pattern) % (d, h, m, s)

Some examples:

$ sec2time(10, 3)
Out: '00:00:10.000'

$ sec2time(1234567.8910, 0)
Out: '14 days, 06:56:07'

$ sec2time(1234567.8910, 4)
Out: '14 days, 06:56:07.8910'

$ sec2time([12, 345678.9], 3)
Out: ['00:00:12.000', '4 days, 00:01:18.900']
Answered By: ddzzbbwwmm

If you need to get datetime.time value, you can use this trick:

my_time = (datetime(1970,1,1) + timedelta(seconds=my_seconds)).time()

You cannot add timedelta to time, but can add it to datetime.

UPD: Yet another variation of the same technique:

my_time = (datetime.fromordinal(1) + timedelta(seconds=my_seconds)).time()

Instead of 1 you can use any number greater than 0. Here we use the fact that datetime.fromordinal will always return datetime object with time component being zero.

Answered By: MarSoft

This is my quick trick:

from humanfriendly import format_timespan
secondsPassed = 1302
# '21 minutes and 42 seconds'

For more info Visit:

Answered By: doories

dateutil.relativedelta is convenient if you need to access hours, minutes and seconds as floats as well. datetime.timedelta does not provide a similar interface.

from dateutil.relativedelta import relativedelta
rt = relativedelta(seconds=5440)
    int(rt.hours), int(rt.minutes), int(rt.seconds)))


Answered By: teekarna

The following set worked for me.

def sec_to_hours(seconds):
    d=["{} hours {} mins {} seconds".format(a, b, c)]
    return d

# ['2 hours 46 mins 40 seconds']

# ['24 hours 1 mins 45 seconds']
Answered By: naive decoder

division = 3623 // 3600 #to hours
division2 = 600 // 60 #to minutes
print (division) #write hours
print (division2) #write minutes

PS My code is unprofessional

You can divide seconds by 60 to get the minutes

import time
seconds = time.time()
minutes = seconds / 60

When you divide it by 60 again, you will get the hours

Answered By: alosha002

hours (h) calculated by floor division (by //) of seconds by 3600 (60 min/hr * 60 sec/min)

minutes (m) calculated by floor division of remaining seconds (remainder from hour calculation, by %) by 60 (60 sec/min)

similarly, seconds (s) by remainder of hour and minutes calculation.

Rest is just string formatting!

def hms(seconds):
    h = seconds // 3600
    m = seconds % 3600 // 60
    s = seconds % 3600 % 60
    return '{:02d}:{:02d}:{:02d}'.format(h, m, s)

print(hms(7500))  # Should print 02h05m00s
Answered By: Sam

In my case I wanted to achieve format
I solved it like this:

timestamp = 28.97000002861023
str(datetime.fromtimestamp(timestamp)+timedelta(hours=-1)).split(' ')[1][:12]
Answered By: Andre

The solutions above will work if you’re looking to convert a single value for "seconds since midnight" on a date to a datetime object or a string with HH:MM:SS, but I landed on this page because I wanted to do this on a whole dataframe column in pandas. If anyone else is wondering how to do this for more than a single value at a time, what ended up working for me was:

 df['datetime'] = datetime.datetime(mydate) +  
                  pandas.to_timedelta(df['seconds_since_midnight'], 's')
Answered By: Jessica Haskins

Here is a way that I always use: (no matter how inefficient it is)

seconds = 19346
def zeroes (num):
    if num < 10: num = "0" + num
    return num

def return_hms(second, apply_zeroes):
    sec = second % 60
    min_ = second // 60 % 60
    hrs = second // 3600
    if apply_zeroes > 0:
       sec = zeroes(sec)
       min_ = zeroes(min_)
       if apply_zeroes > 1:
           hrs = zeroes(hrs)
    return "{}:{}:{}".format(hrs, min_, sec)

print(return_hms(seconds, 1))


Syntax of return_hms() function

The return_hms() function is used like this:

The first variable (second) is the amount of seconds you want to convert into h:m:s.

The second variable (apply_zeroes) is formatting:

0 or less: Apply no zeroes whatsoever

1: Apply zeroes to minutes and seconds when they’re below 10.

2 or more: Apply zeroes to any value (including hours) when they’re below 10.

Answered By: Lucas Urban

Here is a simple program that reads the current time and converts it to a time of day in hours, minutes, and seconds

import time as tm #import package time
timenow = tm.ctime() #fetch local time in string format

timeinhrs = timenow[11:19]

t=tm.time()#time.time() gives out time in seconds since epoch.

print("Time in HH:MM:SS format is: ",timeinhrs,"nTime since epoch is : ",t/(3600*24),"days")

The output is

Time in HH:MM:SS format is:  13:32:45 
Time since epoch is :  18793.335252338384 days
Answered By: Vijayendra Dwari

A bit off topic answer but maybe useful to someone

def time_format(seconds: int):
    if seconds is not None:
        seconds = int(seconds)
        d = seconds // (3600 * 24)
        h = seconds // 3600 % 24
        m = seconds % 3600 // 60
        s = seconds % 3600 % 60
        if d > 0:
            return '{:02d}D {:02d}H {:02d}m {:02d}s'.format(d, h, m, s)
        elif h > 0:
            return '{:02d}H {:02d}m {:02d}s'.format(h, m, s)
        elif m > 0:
            return '{:02d}m {:02d}s'.format(m, s)
        elif s > 0:
            return '{:02d}s'.format(s)
    return '-'

Results in:

print(time_format(25*60*60 + 125)) 
>>> 01D 01H 02m 05s
print(time_format(17*60*60 + 35)) 
>>> 17H 00m 35s
>>> 58m 20s
>>> 21s
Answered By: Tomas Trdla

I looked every answers here and still tried my own

def a(t):
  print(f"{int(t/3600)}H {int((t/60)%60) if t/3600>0 else int(t/60)}M {int(t%60)}S")


>>> a(7500)
2H 5M 0S
>>> a(3666)
1H 1M 6S

Python: 3.8.8

Answered By: onlyvinish
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