get file list of files contained in a zip file
Question:
I have a zip archive: my_zip.zip. Inside it is one txt file, the name of which I do not know. I was taking a look at Python’s zipfile module ( http://docs.python.org/library/zipfile.html ), but couldn’t make too much sense of what I’m trying to do.
How would I do the equivalent of ‘double-clicking’ the zip file to get the txt file and then use the txt file so I can do:
>>> f = open('my_txt_file.txt','r')
>>> contents = f.read()
Answers:
import zipfile
zip=zipfile.ZipFile('my_zip.zip')
f=zip.open('my_txt_file.txt')
contents=f.read()
f.close()
You can see the documentation here. In particular, the namelist() method will give you the names of the zip file members.
What you need is ZipFile.namelist() that will give you a list of all the contents of the archive, you can then do a zip.open('filename_you_discover') to get the contents of that file.
import zipfile
# zip file handler
zip = zipfile.ZipFile('filename.zip')
# list available files in the container
print (zip.namelist())
# extract a specific file from the zip container
f = zip.open("file_inside_zip.txt")
# save the extraced file
content = f.read()
f = open('file_inside_zip.extracted.txt', 'wb')
f.write(content)
f.close()
I have a zip archive: my_zip.zip. Inside it is one txt file, the name of which I do not know. I was taking a look at Python’s zipfile module ( http://docs.python.org/library/zipfile.html ), but couldn’t make too much sense of what I’m trying to do.
How would I do the equivalent of ‘double-clicking’ the zip file to get the txt file and then use the txt file so I can do:
>>> f = open('my_txt_file.txt','r')
>>> contents = f.read()
import zipfile
zip=zipfile.ZipFile('my_zip.zip')
f=zip.open('my_txt_file.txt')
contents=f.read()
f.close()
You can see the documentation here. In particular, the namelist() method will give you the names of the zip file members.
What you need is ZipFile.namelist() that will give you a list of all the contents of the archive, you can then do a zip.open('filename_you_discover') to get the contents of that file.
import zipfile
# zip file handler
zip = zipfile.ZipFile('filename.zip')
# list available files in the container
print (zip.namelist())
# extract a specific file from the zip container
f = zip.open("file_inside_zip.txt")
# save the extraced file
content = f.read()
f = open('file_inside_zip.extracted.txt', 'wb')
f.write(content)
f.close()