# How to format a floating number to fixed width in Python

## Question:

How do I format a floating number to a fixed width with the following requirements:

- Leading zero if n < 1
- Add trailing decimal zero(s) to fill up fixed width
- Truncate decimal digits past fixed width
- Align all decimal points

For example:

```
% formatter something like '{:06}'
numbers = [23.23, 0.123334987, 1, 4.223, 9887.2]
for number in numbers:
print formatter.format(number)
```

The output would be like

```
23.2300
0.1233
1.0000
4.2230
9887.2000
```

## Answers:

```
numbers = [23.23, 0.1233, 1.0, 4.223, 9887.2]
for x in numbers:
print("{:10.4f}".format(x))
```

prints

```
23.2300
0.1233
1.0000
4.2230
9887.2000
```

The format specifier inside the curly braces follows the Python format string syntax. Specifically, in this case, it consists of the following parts:

- The
*empty string*before the colon means "take the next provided argument to`format()`

" – in this case the`x`

as the only argument. - The
`10.4f`

part after the colon is the format specification. - The
`f`

denotes fixed-point notation. - The
`10`

is the total width of the field being printed, lefted-padded by spaces. - The
`4`

is the number of digits after the decimal point.

In python3 the following works:

```
>>> v=10.4
>>> print('% 6.2f' % v)
10.40
>>> print('% 12.1f' % v)
10.4
>>> print('%012.1f' % v)
0000000010.4
```

See Python 3.x format string syntax:

```
IDLE 3.5.1
numbers = ['23.23', '.1233', '1', '4.223', '9887.2']
for x in numbers:
print('{0: >#016.4f}'. format(float(x)))
23.2300
0.1233
1.0000
4.2230
9887.2000
```

In Python 3.

```
GPA = 2.5
print(" %6.1f " % GPA)
```

`6.1f`

means after the dots 1 digits show if you print 2 digits after the dots you should only `%6.2f`

such that `%6.3f`

3 digits print after the point.

It has been a few years since this was answered, **but as of Python 3.6** (PEP498) you could use the new `f-strings`

:

```
numbers = [23.23, 0.123334987, 1, 4.223, 9887.2]
for number in numbers:
print(f'{number:9.4f}')
```

**Prints:**

```
23.2300
0.1233
1.0000
4.2230
9887.2000
```

You can also left pad with zeros. For example if you want `number`

to have 9 characters length, left padded with zeros use:

`print('{:09.3f}'.format(number))`

Thus, if `number = 4.656`

, the output is: `00004.656`

For your example the output will look like this:

```
numbers = [23.2300, 0.1233, 1.0000, 4.2230, 9887.2000]
for x in numbers:
print('{:010.4f}'.format(x))
```

prints:

```
00023.2300
00000.1233
00001.0000
00004.2230
09887.2000
```

One example where this may be useful is when you want to properly list filenames in alphabetical order. I noticed in some linux systems, the number is: 1,10,11,..2,20,21,…

Thus if you want to enforce the necessary numeric order in filenames, you need to left pad with the appropriate number of zeros.

I needed something similar for arrays. That helped me

```
some_array_rounded=np.around(some_array, 5)
```

This will print `76.66`

:

```
print("Number: ", f"{76.663254: .2f}")
```

I tried all the options like

`pd.options.display.float_format = '{:.4f}'.format`

`pd.set_option('display.float_format', str)`

`pd.set_option('display.float_format', lambda x: f'%.{len(str(x%1))-2}f' % x)`

`pd.set_option('display.float_format', lambda x: '%.3f' % x)`

but nothing worked for me.

so while assigning the variable/value (`var1`

) to a variable (say `num1`

) I used `round(val,5)`

like

```
num1 = round(var1,5)
```

This is a crude method as you have to use this round function in each assignment. But this ensures you control on how it happens and get what you want.

Using f-string literals:

```
>>> number = 12.34
>>> print(f"{number}")
12.34
>>> print(f"{number:10f}")
12.340000
>>> print(f"{number:10.4f}")
12.3400
```

The `10.4f`

after the colon `:`

is the format specification, with 10 being the width in characters of the whole number (including spaces), and the second number 4 being the number of decimal places, and the `f`

standing for floating-point number.

It’s also possible to use variables instead of hard-coding the width and the number of decimal places:

```
>>> number = 12.34
>>> width = 10
>>> decimals = 4
>>> print(f"{number:{width}.{decimals}f}")
12.3400
```