Python arguments as a dictionary

Question

How can I get argument names and their values passed to a method as a dictionary?

I want to specify the optional and required parameters for a GET request as part of a HTTP API in order to build the URL. I’m not sure of the best way to make this pythonic.

Asked By: Sean W.

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Source

Answer 1

Use a single argument prefixed with **.

>>> def foo(**args):
...     print(args)
...
>>> foo(a=1, b=2)
{'a': 1, 'b': 2}

Answered By: Fred Foo

Answer 2

For non-keyworded arguments, use a single *, and for keyworded arguments, use a **.

For example:

def test(*args, **kwargs):
    print args
    print kwargs

>>test(1, 2, a=3, b=4)
(1, 2)
{'a': 3, 'b': 4}

Non-keyworded arguments would be unpacked to a tuple and keyworded arguments would be unpacked to a dictionary.
Unpacking Argument Lists

Answered By: Bhargav Mangipudi

Python arguments as a dictionary

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