itertools.ifilter Vs. filter Vs. list comprehensions

Question

I am trying to become more familiar with the itertools module and have found a function called ifilter.

From what I understand, it filters and iterable based on the given function and returns an iterator over a list containing the elements of the iterable on which the function evaluates to True.

Question 1: is my understanding thus far correct?

Question 2: aside from the fact that this returns and iterator, how is it different from the built-in filter function?

Question 3 Which is faster?

From what I can tell, it is not. Am I missing something? (I ran the following test)

>>> itertools.ifilter(lambda x: x%2, range(5))
<itertools.ifilter object at 0x7fb1a101b210>
>>> for i in itertools.ifilter(lambda x: x%2, range(5)): print i
... 
1
3
>>> filter(lambda x: x%2, range(5))
[1, 3]
>>> function = lambda x: x%2
>>> [item for item in range(5) if function(item)]
[1,3]

Asked By: inspectorG4dget

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Source

Answer 1

ifilter returns a generator, not a list.

Generators create their items on the fly when needed, instead of allocating the entire list first. That’s the only difference between ifilter and filter

Answered By: Dor Shemer

Answer 2

Here, you can see the diference:

filter(function, iterable): Construct a list from those elements of iterable for which function returns true.

itertools.ifilter(predicate, iterable): Make an iterator that filters elements from iterable returning only those for which the predicate is True.

This means that to obtain ‘ifiltered’ items you should iterate with returned iterator, but ‘filter’ returns all elements in a list with out iteration needed.

Answered By: dani herrera

Answer 3

Your understanding is correct: the only difference is that ifilter returns an iterator, while using filter is like calling:

list(ifilter(...))

You may also be interested in what PEP 289 says about filter and ifilter:

List comprehensions greatly reduced the need for filter() and map(). Likewise, generator expressions are expected to minimize the need for itertools.ifilter() and itertools.imap(). […]

Also note that ifilter became filter in Python-3 (hence removed from itertools).

Answered By: Rik Poggi

Answer 4

The example below includes a number generator that prints a message immediately before yielding the number, shows up how filter() first builds the list, then runs through that and filters it. Whereas itertools.ifilter filters as it goes, never building a list. If you’re filtering 500,000 significant things, you want ifilter, so you’re not building a list.

import itertools

def number_generator():
    for i in range(0, 3):
        print "yield", i
        yield i
    print "stopping"

function = lambda x: x > 0

numbers = number_generator()
print "itertools.ifilter:"
for n in itertools.ifilter(function, numbers):
    print n

print "nfilter:"
numbers = number_generator()
for n in filter(function, numbers):
    print n

Output:

itertools.ifilter:
yield 0
yield 1
1
yield 2
2
stopping

filter:
yield 0
yield 1
yield 2
stopping
1
2

Answered By: tobych

itertools.ifilter Vs. filter Vs. list comprehensions

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