Extract element with no class attribute
Question:
I need to navigate to an html element of a particular type.
However, there are many such elements of that type on the page, with many different classes.
I need one which does not have any class attribute.
Should I look for one with class == '', or is there some other way?
Answers:
Use
soup.findAll(attrs={'class': None})
Quoting from docs:
You can use attrs if you need to put restrictions on attributes whose names are Python reserved words, like class, for, or import; or attributes whose names are non-keyword arguments to the Beautiful Soup search methods: name, recursive, limit, text, or attrs itself.
As of Beautiful Soup version 4.1.2, you can use the class_ keyword argument.
To select an element without a class attribute, you can just specify None:
soup.find_all(class_=None)
Alternatively, specifying False also works:
soup.find_all(class_=False)
I need to navigate to an html element of a particular type.
However, there are many such elements of that type on the page, with many different classes.
I need one which does not have any class attribute.
Should I look for one with class == '', or is there some other way?
Use
soup.findAll(attrs={'class': None})
Quoting from docs:
You can use attrs if you need to put restrictions on attributes whose names are Python reserved words, like class, for, or import; or attributes whose names are non-keyword arguments to the Beautiful Soup search methods: name, recursive, limit, text, or attrs itself.
As of Beautiful Soup version 4.1.2, you can use the class_ keyword argument.
To select an element without a class attribute, you can just specify None:
soup.find_all(class_=None)
Alternatively, specifying False also works:
soup.find_all(class_=False)