How to check if the string is empty?


Does Python have something like an empty string variable where you can do:

if myString == string.empty:

Regardless, what’s the most elegant way to check for empty string values? I find hard coding "" every time for checking an empty string not as good.

Asked By: Joan Venge



Empty strings are "falsy" (python 2 or python 3 reference), which means they are considered false in a Boolean context, so you can just do this:

if not myString:

This is the preferred way if you know that your variable is a string. If your variable could also be some other type then you should use:

if myString == "":

See the documentation on Truth Value Testing for other values that are false in Boolean contexts.

Answered By: Andrew Clark

The most elegant way would probably be to simply check if its true or falsy, e.g.:

if not my_string:

However, you may want to strip white space because:

 >>> bool("")
 >>> bool("   ")
 >>> bool("   ".strip())

You should probably be a bit more explicit in this however, unless you know for sure that this string has passed some kind of validation and is a string that can be tested this way.

Answered By: Bartek

From PEP 8, in the “Programming Recommendations” section:

For sequences, (strings, lists, tuples), use the fact that empty sequences are false.

So you should use:

if not some_string:


if some_string:

Just to clarify, sequences are evaluated to False or True in a Boolean context if they are empty or not. They are not equal to False or True.

Answered By: zenpoy

if stringname: gives a false when the string is empty. I guess it can’t be simpler than this.

Answered By: Kakashi

If you want to differentiate between empty and null strings, I would suggest using if len(string), otherwise, I’d suggest using simply if string as others have said. The caveat about strings full of whitespace still applies though, so don’t forget to strip.

Answered By: Silas Ray
a = ''
b = '   '
a.isspace() -> False
b.isspace() -> True
Answered By: Roman Semirook

You may have a look at this Assigning empty value or string in Python

This is about comparing strings that are empty. So instead of testing for emptiness with not, you may test is your string is equal to empty string with "" the empty string…

Answered By: kiriloff

I would test noneness before stripping. Also, I would use the fact that empty strings are False (or Falsy). This approach is similar to Apache’s StringUtils.isBlank or Guava’s Strings.isNullOrEmpty

This is what I would use to test if a string is either None OR Empty OR Blank:

def isBlank (myString):
    return not (myString and myString.strip())

And, the exact opposite to test if a string is not None NOR Empty NOR Blank:

def isNotBlank (myString):
    return bool(myString and myString.strip())
Answered By: rouble

As prmatta posted above, but with mistake.

def isNoneOrEmptyOrBlankString (myString):
    if myString:
        if not myString.strip():
            return True
            return False
    return False
Answered By: Shadow

I once wrote something similar to Bartek’s answer and javascript inspired:

def is_not_blank(s):
    return bool(s and not s.isspace())


print is_not_blank("")    # False
print is_not_blank("   ") # False
print is_not_blank("ok")  # True
print is_not_blank(None)  # False
Answered By: vault

for those who expect a behaviour like the apache StringUtils.isBlank or Guava Strings.isNullOrEmpty :

if mystring and mystring.strip():
    print "not blank string"
    print "blank string"
Answered By: kommradHomer

Test empty or blank string (shorter way):

if myString.strip():
    print("it's not an empty or blank string")
    print("it's an empty or blank string")
Answered By: prrvchr

How about this? Perhaps it’s not “the most elegant”, but it seems pretty complete and clear:

if (s is None) or (str(s).strip()==""): // STRING s IS "EMPTY"...
Answered By: BuvinJ

When you are reading file by lines and want to determine, which line is empty, make sure you will use .strip(), because there is new line character in “empty” line:

lines = open("my_file.log", "r").readlines()

for line in lines:
    if not line.strip():

    # your code for non-empty lines
Answered By: Pavel Štěrba

I find hardcoding(sic) "" every time for checking an empty string not as good.

Clean code approach

Doing this: foo == "" is very bad practice. "" is a magical value. You should never check against magical values (more commonly known as magical numbers)

What you should do is compare to a descriptive variable name.

Descriptive variable names

One may think that "empty_string" is a descriptive variable name. It isn’t.

Before you go and do empty_string = "" and think you have a great variable name to compare to. This is not what "descriptive variable name" means.

A good descriptive variable name is based on its context.
You have to think about what the empty string is.

  • Where does it come from.
  • Why is it there.
  • Why do you need to check for it.

Simple form field example

You are building a form where a user can enter values. You want to check if the user wrote something or not.

A good variable name may be not_filled_in

This makes the code very readable

if == not_filled_in:
    raise ValueError("We need your name")

Thorough CSV parsing example

You are parsing CSV files and want the empty string to be parsed as None

(Since CSV is entirely text based, it cannot represent None without using predefined keywords)

A good variable name may be CSV_NONE

This makes the code easy to change and adapt if you have a new CSV file that represents None with another string than ""

if csvfield == CSV_NONE:
    csvfield = None

There are no questions about if this piece of code is correct. It is pretty clear that it does what it should do.

Compare this to

if csvfield == EMPTY_STRING:
    csvfield = None

The first question here is, Why does the empty string deserve special treatment?

This would tell future coders that an empty string should always be considered as None.

This is because it mixes business logic (What CSV value should be None) with code implementation (What are we actually comparing to)

There needs to be a separation of concern between the two.

Answered By: firelynx

Responding to @1290. Sorry, no way to format blocks in comments. The None value is not an empty string in Python, and neither is (spaces). The answer from Andrew Clark is the correct one: if not myString. The answer from @rouble is application-specific and does not answer the OP’s question. You will get in trouble if you adopt a peculiar definition of what is a “blank” string. In particular, the standard behavior is that str(None) produces 'None', a non-blank string.

However if you must treat None and (spaces) as “blank” strings, here is a better way:

class weirdstr(str):
    def __new__(cls, content):
        return str.__new__(cls, content if content is not None else '')
    def __nonzero__(self):
        return bool(self.strip())


>>> normal = weirdstr('word')
>>> print normal, bool(normal)
word True

>>> spaces = weirdstr('   ')
>>> print spaces, bool(spaces)

>>> blank = weirdstr('')
>>> print blank, bool(blank)

>>> none = weirdstr(None)
>>> print none, bool(none)

>>> if not spaces:
...     print 'This is a so-called blank string'
This is a so-called blank string

Meets the @rouble requirements while not breaking the expected bool behavior of strings.

Answered By: Chris Johnson
not str(myString)

This expression is True for strings that are empty. Non-empty strings, None and non-string objects will all produce False, with the caveat that objects may override __str__ to thwart this logic by returning a falsy value.

Answered By: Fax

If you just use

not var1 

it is not possible to difference a variable which is boolean False from an empty string '':

var1 = ''
not var1
> True

var1 = False
not var1
> True

However, if you add a simple condition to your script, the difference is made:

var1  = False
not var1 and var1 != ''
> True

var1 = ''
not var1 and var1 != ''
> False
Answered By: jberrio

In case this is useful to someone, here is a quick function i built out to replace blank strings with N/A’s in lists of lists (python 2).

y = [["1","2",""],["1","4",""]]

def replace_blank_strings_in_lists_of_lists(list_of_lists):
    new_list = []
    for one_list in list_of_lists:
        new_one_list = []
        for element in one_list:
            if element:
    return new_list

x= replace_blank_strings_in_lists_of_lists(y)
print x

This is useful for posting lists of lists to a mysql database that does not accept blanks for certain fields (fields marked as NN in schema. in my case, this was due to a composite primary key).

Answered By: FlyingZebra1

The only really solid way of doing this is the following:

if "".__eq__(myString):

All other solutions have possible problems and edge cases where the check can fail.

  • len(myString) == 0 can fail if myString is an object of a class that inherits from str and overrides the __len__() method.

  • myString == "" and myString.__eq__("") can fail if myString overrides __eq__() and __ne__().

  • "" == myString also gets fooled if myString overrides __eq__().

  • myString is "" and "" is myString are equivalent. They will both fail if myString is not actually a string but a subclass of string (both will return False). Also, since they are identity checks, the only reason why they work is because Python uses String Pooling (also called String Internment) which uses the same instance of a string if it is interned (see here: Why does comparing strings using either '==' or 'is' sometimes produce a different result?). And "" is interned from the start in CPython

    The big problem with the identity check is that String Internment is (as far as I could find) that it is not standardised which strings are interned. That means, theoretically "" is not necessary interned and that is implementation dependant.

    Also, comparing strings using is in general is a pretty evil trap since it will work correctly sometimes, but not at other times, since string pooling follows pretty strange rules.

  • Relying on the falsyness of a string may not work if the object overrides __bool__().

The only way of doing this that really cannot be fooled is the one mentioned in the beginning: "".__eq__(myString). Since this explicitly calls the __eq__() method of the empty string it cannot be fooled by overriding any methods in myString and solidly works with subclasses of str.

This is not only theoretical work but might actually be relevant in real usage since I have seen frameworks and libraries subclassing str before and using myString is "" might return a wrong output there.

That said, in most cases all of the mentioned solutions will work correctly. This is post is mostly academic work.

Answered By: Dakkaron

I did some experimentation with strings like ”, ‘ ‘, ‘n’, etc. I want isNotWhitespace to be True if and only if the variable foo is a string with at least one non-whitespace character. I’m using Python 3.6. Here’s what I ended up with:

isWhitespace = str is type(foo) and not foo.strip()
isNotWhitespace = str is type(foo) and not not foo.strip()

Wrap this in a method definition if desired.

Answered By: Tom Stambaugh

If you are not totally sure, that your input is really a string, I would recommend to use isinstance(object, classinfo) link in addition, as shown in the example.

If not, lists or a True bool value could also be evaluated as True.

<script type="text/javascript" src="//"></script>

<div data-datacamp-exercise data-lang="python">
  <code data-type="sample-code">
def test_string(my_string):
    if isinstance(my_string, str) and my_string:
      print("It's a me, String! -> " + my_string)
      print("Nope. No, String")

def not_fully_test_string(my_string):
    if my_string:
      print("It's a me, String??? -> " + str(my_string))
      print("Nope. No, String")
print("Testing String:")
test_string(["string1", "string2"])
test_string("My String")
test_string(" ")

print("nTesting String or not?")
not_fully_test_string(["string1", "string2"])
not_fully_test_string("My String")
not_fully_test_string(" ")


Answered By: Rene

Below is an elegant solution for any number of spaces.

def str_empty(s: str) -> bool:
    """Strip white space and count remaining characters."""
    return len(s.strip()) < 1

>>> str_empty(' ')
Answered By: Adam Erickson

The clearest approach is:

if s == "":


  • Additional indication to the programmer what the type of s should be.
  • "" is not "hard-coding" a magic value any more than x == 0 is.
    Some values are fundamental and do not need a named constant; e.g. x % 2 to check for even numbers.
  • Cannot incorrectly indicate that any falsy value (e.g. []) is an empty string.

Consider how one checks if an integer is 0:

if x == 0:

One certainly should not do:

if not x:

Both integers and strings are primitive value types. Why treat them differently?

Answered By: Mateen Ulhaq

if you want to check if a string is completely empty

if not mystring

which works because empty strings are false
but if a string is only whitespace it will be true so you might want to

if not mystring.strip()
Answered By: wij