Python – possible problem returning a value in a function which can rerun itself Question: # Python code to check input for "" and diving by zero error def getNumber(): x = input("Enter a number to divide 100 by: ") # string!! if x == "": # must check for this first as cant convert …
Leetcode problem asks for the output to be in List[List[int]] but returns a set without converting into a list Question: This is a solution to a leetcode problem. My problem is with why the output below is acceptable? The problem is expecting List[List[int]] but the "res" that is being returned is a set. I don’t …
why a python function still returns "None" though i am explicitly returning a value? Question: def binarySearch(nums,low,high,target): if low<=high: mid=(low+high)//2 if nums[mid]==target: return mid if nums[mid]<target: binarySearch(nums,mid+1,high,target) else: binarySearch(nums,low,mid-1,target) else: return -1 def search(nums, target): return binarySearch(nums,0,len(nums)-1,target) nums=[-1,0,3,5,9,12] target=9 print(search(nums,target)) console output Expected output of the above python code for binary search is ‘4’. But …
How to specify multiple return types using type-hints Question: I have a function in python that can either return a bool or a list. Is there a way to specify the return types using type hints? For example, is this the correct way to do it? def foo(id) -> list or bool: … Asked By: …
Apply pandas function to column to create multiple new columns? Question: How to do this in pandas: I have a function extract_text_features on a single text column, returning multiple output columns. Specifically, the function returns 6 values. The function works, however there doesn’t seem to be any proper return type (pandas DataFrame/ numpy array/ Python …
Why should functions always return the same type? Question: I read somewhere that functions should always return only one type so the following code is considered as bad code: def x(foo): if ‘bar’ in foo: return (foo, ‘bar’) return None I guess the better solution would be def x(foo): if ‘bar’ in foo: return (foo, …
