How to format a float with a maximum number of decimal places and without extra zero padding?
Question:
I need to do some decimal place formatting in python. Preferably, the floating point value should always show at least a starting 0 and one decimal place. Example:
Input: 0
Output: 0.0
Values with more decimal places should continue to show them, until it gets 4 out. So:
Input: 65.53
Output: 65.53
Input: 40.355435
Output: 40.3554
I know that I can use {0.4f} to get it to print out to four decimal places, but it will pad with unwanted 0s. Is there a formatting code to tell it to print out up to a certain number of decimals, but to leave them blank if there is no data? I believe C# accomplishes this with something like:
floatValue.ToString("0.0###")
Where the # symbols represent a place that can be left blank.
Answers:
Sorry, the best I can do:
' {:0.4f}'.format(1./2.).rstrip('0')
Corrected:
ff=1./2.
' {:0.4f}'.format(ff).rstrip('0')+'0'[0:(ff%1==0)]
>>> def pad(float, front = 0, end = 4):
s = '%%%s.%sf' % (front, end) % float
i = len(s)
while i > 0 and s[i - 1] == '0':
i-= 1
if s[i - 1] == '.' and len(s) > i:
i+= 1 # for 0.0
return s[:i] + ' ' * (len(s) - i)
>>> pad(0, 3, 4)
'0.0 '
>>> pad(65.53, 3, 4)
'65.53 '
>>> pad(40.355435, 3, 4)
'40.3554'
What you’re asking for should be addressed by rounding methods like the built-in round
function. Then let the float
number be naturally displayed with its string
representation.
>>> round(65.53, 4) # num decimal <= precision, do nothing
'65.53'
>>> round(40.355435, 4) # num decimal > precision, round
'40.3554'
>>> round(0, 4) # note: converts int to float
'0.0'
From trial and error I think :.15g
is what you want:
In: f"{3/4:.15g}"
Out: '0.75'
In f"{355/113:.15g}"
Out: '3.14159292035398'
(while f"{3/4:.15f}" == '0.750000000000000'
)
I need to do some decimal place formatting in python. Preferably, the floating point value should always show at least a starting 0 and one decimal place. Example:
Input: 0
Output: 0.0
Values with more decimal places should continue to show them, until it gets 4 out. So:
Input: 65.53
Output: 65.53
Input: 40.355435
Output: 40.3554
I know that I can use {0.4f} to get it to print out to four decimal places, but it will pad with unwanted 0s. Is there a formatting code to tell it to print out up to a certain number of decimals, but to leave them blank if there is no data? I believe C# accomplishes this with something like:
floatValue.ToString("0.0###")
Where the # symbols represent a place that can be left blank.
Sorry, the best I can do:
' {:0.4f}'.format(1./2.).rstrip('0')
Corrected:
ff=1./2.
' {:0.4f}'.format(ff).rstrip('0')+'0'[0:(ff%1==0)]
>>> def pad(float, front = 0, end = 4):
s = '%%%s.%sf' % (front, end) % float
i = len(s)
while i > 0 and s[i - 1] == '0':
i-= 1
if s[i - 1] == '.' and len(s) > i:
i+= 1 # for 0.0
return s[:i] + ' ' * (len(s) - i)
>>> pad(0, 3, 4)
'0.0 '
>>> pad(65.53, 3, 4)
'65.53 '
>>> pad(40.355435, 3, 4)
'40.3554'
What you’re asking for should be addressed by rounding methods like the built-in round
function. Then let the float
number be naturally displayed with its string
representation.
>>> round(65.53, 4) # num decimal <= precision, do nothing
'65.53'
>>> round(40.355435, 4) # num decimal > precision, round
'40.3554'
>>> round(0, 4) # note: converts int to float
'0.0'
From trial and error I think :.15g
is what you want:
In: f"{3/4:.15g}"
Out: '0.75'
In f"{355/113:.15g}"
Out: '3.14159292035398'
(while f"{3/4:.15f}" == '0.750000000000000'
)