Making a 0 to n vector in python

Question:

I am a new python user and I was wondering how I could make a 0 to n vector.
I would like the user to be able to input an integer for n, and receive an output of [0,1,2,3,4,5…,n].

This is what I have done so far…

from numpy import matrix

n=int(raw_input("n= "))
for i in range(n, 0, -1):
K = matrix(i)
print K

But this is what I get as an output:

[0][1][2][3][4][5]...[n]

Transposing the matrix doesn’t help.
What am I doing wrong?

Thank you for your help!

Asked By: Xander

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Answers:

Use the built-in function:

range(n)

(Well, should be n+1 if you want a list to be [0, 1, … , n])

Answered By: joe
from numpy import array
n = int(raw_input("n= "))
k = array(range(n+1))
print k
Answered By: John La Rooy

If you want to use numpy, you can make use of arange:

>>> import numpy as np
>>> np.arange(10)
array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
Answered By: Akavall

In plain Python (no NumPy dependency):

arr = list(range(10))
print(arr)

(Posting because even if old, browsing for similar problem go to this one. The range() solution is not optimal depending of further tasks (e.g: remove an item arr.remove(val))).

Answered By: angelito
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