How can I convert a string into a date object and get year, month and day separately?

Question

If I have lets say this string “2008-12-12 19:21:10” how can I convert it into a date and get the year, month and day from that created object separately?

Asked By: Ivan Juarez

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Source

Answer 1

Use the datetime.datetime.strptime() function:

from datetime import datetime
dt = datetime.strptime(datestring, '%Y-%m-%d %H:%M:%S')

Now you have a datetime.datetime object, and it has .year, .month and .day attributes:

>>> from datetime import datetime
>>> datestring = "2008-12-12 19:21:10"
>>> dt = datetime.strptime(datestring, '%Y-%m-%d %H:%M:%S')
>>> print dt.year, dt.month, dt.day
2008 12 12

Answered By: Martijn Pieters

Answer 2

https://www.tutorialspoint.com/python/time_strptime.htm
Here you can find strptime() method complete description. where you can find all type of strings.
Eg:- To convert string like this ’15-MAY-12′

>>>from datetime import datetime
>>>datestring = "15-MAY-12"
>>>dt = datetime.strptime(datestring, '%d-%b-%Y')
>>>print(dt.year, dt.month, dt.day)
 2012 MAY 15

Answered By: user8217035

Answer 3

with milliseconds

>>> from datetime import datetime
>>> datestring = "2018-04-11 23:36:18.886585"
>>> dt = datetime.strptime(datestring, '%Y-%m-%d %H:%M:%S.%f')
>>> print dt.year, dt.month, dt.day
2018 04 11

Answered By: Vijay Krishna

Answer 4

One thing to add; pay attention that %y is for two digit year notation %Y is for the four digit one:

import datetime

datestring = '15-MAY-12'
print(datetime.datetime.strptime(datestring, '%d-%b-%y'))
>>> datetime.datetime(2012, 5, 15, 0, 0)

datestring = '15-MAY-2012'    
print(datetime.datetime.strptime(datestring, '%d-%b-%Y'))
>>> datetime.datetime(2012, 5, 15, 0, 0)

Answered By: Shivid

How can I convert a string into a date object and get year, month and day separately?

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