TypeError: 'encoding' is an invalid keyword argument for this function

Question

My python program has trouble opening a text file. When I use the basic open file for read, I get an ascii error. Someone helped me out by having me add an encoding parameter that works well in Idle, but when I run the program through terminal, I get this error message: “TypeError: ‘encoding’ is an invalid keyword argument for this function” How can I read this text file in to use it’s data?

try:
    import tkinter as tk
    from tkinter import *
except:
    import Tkinter as tk
    from Tkinter import *

import time
import sys
import os
import random

flashcards = {}


def Flashcards(key, trans, PoS):
    if not key in flashcards:
        flashcards[key] = [[trans], [PoS]]
    else:
        x = []
        for item in flashcards[key][0]:
            x.append(item)
        x.append(trans)
        flashcards[key][0] = x
        x = []
        for item in flashcards[key][1]:
            x.append(item)
        x.append(PoS)
        flashcards[key][1] = x


def ImportGaeilge():
    flashcards = {}
    with open('gaeilge_flashcard_mode.txt','r', encoding='utf8') as file:
        for line in file:
            line1 = line.rstrip().split("=")
            key = line1[0]
            trans = line1[1]
            PoS = line1[2]
            Flashcards(key, trans, PoS)

def Gaeilge():
    numberCorrect = 0
    totalCards = 0
    ImportGaeilge()
    wrongCards = {}
    x = input('Hit "ENTER" to begin. (Type "quit" to quit)')
    while x != quit:
        os.system('cls')
        time.sleep(1.3)
        card = flashcards.popitem()
        if card == "":
## WRONG CARDS
            print ("Deck one complete.")
            Gaeilge()
        print("nn")
        print(str(card[0])+":")
        x = input("t:")
        if x == 'quit':
            break
        else:
            right = False
            for item in card[1]:
                if x == card[1]:
                    right = True
                    print("nCorrect!")
                    numberCorrect += 1
            if right == False:
                print(card[0])

        totalCards += 1
        print("Correct answers:", str(numberCorrect) +"/"+str(totalCards))


Gaeilge()

gaeilge_flashcard_mode.txt:

I=mé=(pron) (emphatic)
I=mise=(n/a)
you=tú=(pron) (subject)
you=tusa=(emphatic)
y'all=sibh=(plural)
y'all=sibhse=(emphatic)
he=sé=(pron)
he=é=(n/a)
he=seisean=(emphatic)
he=eisean=(n/a)
she=sí=(pron)
she=í=(n/a)
she=sise=(emphatic)
she=ise=(emphatic)
him=é=(pron)
him=eisean=(emphatic)
her=í=(pron)
her=ise=(emphatic)
her=a=(adj)

Asked By: Keither Fly

||

Source

Answer 1

The terminal you are trying to run this on probably uses Python 2.x as standard.

Try using the command “Python3” specifically in the terminal:

$ Python3 yourfile.py

(Tested and confirmed that 2.7 will give that error and that Python3 handles it just fine.)

Answered By: The Unfun Cat

Answer 2

+1 to The Unfun Cat for a correct answer regarding Linux etc.

For Windows users, however, calling ‘Python3’ generally won’t work. But if you’ve installed Python 3.3 (or if you’ve downloaded and installed Python Launcher for Windows), you can type:

C:scr>py -3 yourfile.py

Actually, this launcher also supports shebang syntax, so adding the following first line to your script’s file will work fairly cross-platform (the /usr/bin is ignored on Windows):

#! /usr/bin/python3

After doing that, assuming that windowspy.exe is the default handler for .py files, you can just type:

C:scr>yourfile.py

And if “.PY” is in your PATHEXT environment variable, you can just type:

C:scr>yourfile

More info:

http://docs.python.org/3/whatsnew/3.3.html

http://www.python.org/dev/peps/pep-0397/

Answered By: Jon Coombs

Answer 3

using io.open() instead of open removed this error for me
eg:

import io
with io.open('gaeilge_flashcard_mode.txt','r', encoding='utf8') as file:
    for line in file:
        line1 = line.rstrip().split("=")
        key = line1[0]
        trans = line1[1]
        PoS = line1[2]
        Flashcards(key, trans, PoS)

reference: see this answer

Answered By: Jose Kj

TypeError: 'encoding' is an invalid keyword argument for this function

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