How can I run a celery periodic task from the shell manually?
Question:
I’m using celery and django-celery. I have defined a periodic task that I’d like to test. Is it possible to run the periodic task from the shell manually so that I view the console output?
Answers:
Have you tried just running the task from the Django shell? You can use the .apply method of a task to ensure that it is run eagerly and locally.
Assuming the task is called my_task in Django app myapp in a tasks submodule:
$ python manage.py shell
>>> from myapp.tasks import my_task
>>> eager_result = my_task.apply()
The result instance has the same API as the usual AsyncResult type, except that the result is always evaluated eagerly and locally and the .apply() method will block until the task is run to completion.
I think you’ll need to open two shells: one for executing tasks from the Python/Django shell, and one for running celery worker (python manage.py celery worker). And as the previous answer said, you can run tasks using apply() or apply_async()
I’ve edited the answer so you’re not using a deprecated command.
If you means just trigger a task when the condition is not satisfied, for example, the periodic time not meet. You can do it in two steps.
1.Get your task id.
You can do it by typing.
celery inspect registered
You will see something like app.tasks.update_something.
If nothing, it is probably that celery was not started. Just run it.
2.Run the task with celery call
celery call app.tasks.update_something
For more details, just type
celery --help
celery inspect --help
celery call --help
I’m using celery and django-celery. I have defined a periodic task that I’d like to test. Is it possible to run the periodic task from the shell manually so that I view the console output?
Have you tried just running the task from the Django shell? You can use the .apply method of a task to ensure that it is run eagerly and locally.
Assuming the task is called my_task in Django app myapp in a tasks submodule:
$ python manage.py shell
>>> from myapp.tasks import my_task
>>> eager_result = my_task.apply()
The result instance has the same API as the usual AsyncResult type, except that the result is always evaluated eagerly and locally and the .apply() method will block until the task is run to completion.
I think you’ll need to open two shells: one for executing tasks from the Python/Django shell, and one for running celery worker (python manage.py celery worker). And as the previous answer said, you can run tasks using apply() or apply_async()
I’ve edited the answer so you’re not using a deprecated command.
If you means just trigger a task when the condition is not satisfied, for example, the periodic time not meet. You can do it in two steps.
1.Get your task id.
You can do it by typing.
celery inspect registered
You will see something like app.tasks.update_something.
If nothing, it is probably that celery was not started. Just run it.
2.Run the task with celery call
celery call app.tasks.update_something
For more details, just type
celery --help
celery inspect --help
celery call --help