Applying a function to values in dict

Question

I want to apply a function to all values in dict and store that in a separate dict. I am just trying to see how I can play with python and want to see how I can rewrite something like this

for i in d:
    d2[i] = f(d[i])

to something like

d2[i] = f(d[i]) for i in d

The first way of writing it is of course fine, but I am trying to figure how python syntax can be changed

Asked By: chrise

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Source

Answer 1

d2 = dict((k, f(v)) for k,v in d.items())

Answered By: Alexey Kachayev

Answer 2

If you’re using Python 2.7 or 3.x:

d2 = {k: f(v) for k, v in d1.items()}

Which is equivalent to:

d2 = {}
for k, v in d1.items():
    d2[k] = f(v)

Otherwise:

d2 = dict((k, f(v)) for k, v in d1.items())

Answered By: Joel Cornett

Answer 3

Dictionaries can be nested in Python and in this case the solution d2 = {k: f(v) for k, v in d1.items()} will not work.

For nested dictionaries one needs some function to transverse the whole data structure. For instance if values are allowed to be themselves dictionaries, one can define a function like:

def myfun(d):
  for k, v in d.iteritems():
    if isinstance(v, dict):
      d[k] = myfun(v)
    else:
      d[k] = f(v)
  return d

And then

d2 = myfun(d)

Answered By: user2314737

Answer 4

You could use map:

d2 = dict(d, map(f, d.values()))

If you don’t mind using an extension. You can also use valmap in the toolz library which is functionally equivalent to using the map solution:

from toolz.dicttoolz import valmap

d2 = valmap(f, d)

If not for the clean presentation of the method, you also have the option of supplying a default return class as well, for people that need something other than a dict.

Answered By: Jab

Applying a function to values in dict

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