Putting an if-elif-else statement on one line?

If you only need different expressions for different cases then this may work for you:

expr1 if condition1 else expr2 if condition2 else expr

For example:

a = "neg" if b<0 else "pos" if b>0 else "zero"

Just nest another if clause in the else statement. But that doesn’t make it look any prettier.

>>> x=5
>>> x if x>0 else ("zero" if x==0 else "invalid value")
5
>>> x = 0
>>> x if x>0 else ("zero" if x==0 else "invalid value")
'zero'
>>> x = -1
>>> x if x>0 else ("zero" if x==0 else "invalid value")
'invalid value'

It also depends on the nature of your expressions. The general advice on the other answers of "not doing it" is quite valid for generic statements and generic expressions.

But if all you need is a "dispatch" table, like, calling a different function depending on the value of a given option, you can put the functions to call inside a dictionary.

Something like:

def save(): 
   ...
def edit():
   ...
options = {"save": save, "edit": edit, "remove": lambda : "Not Implemented"}

option = get_input()
result = options[option]()

Instead of an if-else:

if option=="save":
    save()
...

People have already mentioned ternary expressions. Sometimes with a simple conditional assignment as your example, it is possible to use a mathematical expression to perform the conditional assignment. This may not make your code very readable, but it does get it on one fairly short line. Your example could be written like this:

x = 2*(i>100) | 1*(i<100)

The comparisons would be True or False, and when multiplying with numbers would then be either 1 or 0. One could use a + instead of an | in the middle.

There’s an alternative that’s quite unreadable in my opinion but I’ll share anyway just as a curiosity:

x = (i>100 and 2) or (i<100 and 1) or 0

More info here: https://docs.python.org/3/library/stdtypes.html#boolean-operations-and-or-not

You can optionally actually use the get method of a dict:

x = {i<100: -1, -10<=i<=10: 0, i>100: 1}.get(True, 2)

You don’t need the get method if one of the keys is guaranteed to evaluate to True:

x = {i<0: -1, i==0: 0, i>0: 1}[True]

At most one of the keys should ideally evaluate to True. If more than one key evaluates to True, the results could seem unpredictable.

You can use nested ternary if statements.

# if-else ternary construct
country_code = 'USA'
is_USA = True if country_code == 'USA' else False
print('is_USA:', is_USA)

# if-elif-else ternary construct
# Create function to avoid repeating code.
def get_age_category_name(age):
    age_category_name = 'Young' if age <= 40 else ('Middle Aged' if age > 40 and age <= 65 else 'Senior')
    return age_category_name

print(get_age_category_name(25))
print(get_age_category_name(50))
print(get_age_category_name(75))

if i > 100:
    x = 2
elif i < 100:
    x = 1
else:
    x = 0

If you want to use the above-mentioned code in one line, you can use the following:

x = 2 if i > 100 else 1 if i < 100 else 0

On doing so, x will be assigned 2 if i > 100, 1 if i < 100 and 0 if i = 100

The ternary operator is the best way to a concise expression. The syntax is variable = value_1 if condition else value_2. So, for your example, you must apply the ternary operator twice:

i = 23 # set any value for i
x = 2 if i > 100 else 1 if i < 100 else 0

Despite some other answers: YES it IS possible:

if expression1:
   statement1
elif expression2:
   statement2
else:
   statement3

translates to the following one liner:

statement1 if expression1 else (statement2 if expression2 else statement3)

in fact you can nest those till infinity. Enjoy 😉

MESSAGELENGHT = 39
"A normal function call using if elif and else."
if MESSAGELENGHT == 16:
    Datapacket = "word"
elif MESSAGELENGHT == 8:
     Datapacket = 'byte'
else:
     Datapacket = 'bit'

#similarly for a oneliner expresion:
    

Datapacket = "word" if MESSAGELENGHT == 16 else 'byte' if MESSAGELENGHT == 8 else 'bit'
print(Datapacket)

Thanks

Nested ternary operator is the best solution —

Example case –

4 = 1

3 = 2

2 = 3

1 = 4

a = 4

prio = 4 if a == 1 else (3 if a == 2 else (2 if a == 3 else 1))

yes you can by doing this :

i = int(input('type your num here : '))

x = 2 if i > 100 else ( 1 if i < 100 else 0)
print (x)