Call Python script from bash with argument

Question

I know that I can run a python script from my bash script using the following:

python python_script.py

But what about if I wanted to pass a variable / argument to my python script from my bash script. How can I do that?

Basically bash will work out a filename and then python will upload it, but I need to send the filename from bash to python when I call it.

Asked By: Jimmy

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Source

Answer 1

Use

python python_script.py filename

and in your Python script

import sys
print sys.argv[1]

Answered By: NPE

Answer 2

Beside sys.argv, also take a look at the argparse module, which helps define options and arguments for scripts.

The argparse module makes it easy to write user-friendly command-line interfaces.

Answered By: miku

Answer 3

and take a look at the getopt module.
It works quite good for me!

Answered By: HappyHacking

Answer 4

use in the script:

echo $(python python_script.py arg1 arg2) > /dev/null

or

python python_script.py "string arg"  > /dev/null

The script will be executed without output.

Answered By: burseaner

Answer 5

Embedded option:

Wrap python code in a bash function.

#!/bin/bash

function current_datetime {
python - <<END
import datetime
print datetime.datetime.now()
END
}

# Call it
current_datetime

# Call it and capture the output
DT=$(current_datetime)
echo Current date and time: $DT

Use environment variables, to pass data into to your embedded python script.

#!/bin/bash

function line {
PYTHON_ARG="$1" python - <<END
import os
line_len = int(os.environ['PYTHON_ARG'])
print '-' * line_len
END
}

# Do it one way
line 80

# Do it another way
echo $(line 80)

http://bhfsteve.blogspot.se/2014/07/embedding-python-in-bash-scripts.html

Answered By: user77115

Answer 6

To execute a python script in a bash script you need to call the same command that you would within a terminal. For instance

> python python_script.py var1 var2

To access these variables within python you will need

import sys
print(sys.argv[0]) # prints python_script.py
print(sys.argv[1]) # prints var1
print(sys.argv[2]) # prints var2

Answered By: iamthedrake

Answer 7

I have a bash script that calls a small python routine to display a message window. As I need to use killall to stop the python script I can’t use the above method as it would then mean running killall python which could take out other python programmes so I use

pythonprog.py "$argument" & # The & returns control straight to the bash script so must be outside the backticks. The preview of this message is showing it without “`” either side of the command for some reason.

As long as the python script will run from the cli by name rather than python pythonprog.py this works within the script. If you need more than one argument just use a space between each one within the quotes.

Answered By: Dave Thebuskeruk

Answer 8

Print all args without the filename:

for i in range(1, len(sys.argv)):
print(sys.argv[i])

Answered By: Riade

Call Python script from bash with argument

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