Proxy with urllib2

Question:

I open urls with:

site = urllib2.urlopen('http://google.com')

And what I want to do is connect the same way with a proxy
I got somewhere telling me:

site = urllib2.urlopen('http://google.com', proxies={'http':'127.0.0.1'})

but that didn’t work either.

I know urllib2 has something like a proxy handler, but I can’t recall that function.

Asked By: Chris Stryker

||

Answers:

You have to install a ProxyHandler

urllib2.install_opener(
    urllib2.build_opener(
        urllib2.ProxyHandler({'http': '127.0.0.1'})
    )
)
urllib2.urlopen('http://www.google.com')
Answered By: dcrosta
proxy = urllib2.ProxyHandler({'http': '127.0.0.1'})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
urllib2.urlopen('http://www.google.com')
Answered By: ZelluX

To use the default system proxies (e.g. from the http_support environment variable), the following works for the current request (without installing it into urllib2 globally):

url = 'http://www.example.com/'
proxy = urllib2.ProxyHandler()
opener = urllib2.build_opener(proxy)
in_ = opener.open(url)
in_.read()
Answered By: blueyed

You can set proxies using environment variables.

import os
os.environ['http_proxy'] = '127.0.0.1'
os.environ['https_proxy'] = '127.0.0.1'

urllib2 will add proxy handlers automatically this way. You need to set proxies for different protocols separately otherwise they will fail (in terms of not going through proxy), see below.

For example:

proxy = urllib2.ProxyHandler({'http': '127.0.0.1'})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
urllib2.urlopen('http://www.google.com')
# next line will fail (will not go through the proxy) (https)
urllib2.urlopen('https://www.google.com')

Instead

proxy = urllib2.ProxyHandler({
    'http': '127.0.0.1',
    'https': '127.0.0.1'
})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
# this way both http and https requests go through the proxy
urllib2.urlopen('http://www.google.com')
urllib2.urlopen('https://www.google.com')
Answered By: cashmere

In Addition to the accepted answer:
My scipt gave me an error

File "c:Python23liburllib2.py", line 580, in proxy_open
    if '@' in host:
TypeError: iterable argument required

Solution was to add http:// in front of the proxy string:

proxy = urllib2.ProxyHandler({'http': 'http://proxy.xy.z:8080'})
opener = urllib2.build_opener(proxy)
urllib2.install_opener(opener)
urllib2.urlopen('http://www.google.com')
Answered By: HCC

In addition set the proxy for the command line session
Open a command line where you might want to run your script

netsh winhttp set proxy YourProxySERVER:yourProxyPORT

run your script in that terminal.

Answered By: pensebien

One can also use requests if we would like to access a web page using proxies. Python 3 code:

>>> import requests
>>> url = 'http://www.google.com'
>>> proxy = '169.50.87.252:80'
>>> requests.get(url, proxies={"http":proxy})
<Response [200]>

More than one proxies can also be added.

>>> proxy1 = '169.50.87.252:80'
>>> proxy2 = '89.34.97.132:8080'
>>> requests.get(url, proxies={"http":proxy1,"http":proxy2})
<Response [200]>
Answered By: Waqar Detho
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