How to convert a date string to different format
Question:
I need to convert date string “2013-1-25” to string “1/25/13” in python.
I looked at the datetime.strptime but still can’t find a way for this.
Answers:
I assume I have import datetime before running each of the lines of code below
datetime.datetime.strptime("2013-1-25", '%Y-%m-%d').strftime('%m/%d/%y')
prints "01/25/13".
If you can’t live with the leading zero, try this:
dt = datetime.datetime.strptime("2013-1-25", '%Y-%m-%d')
print '{0}/{1}/{2:02}'.format(dt.month, dt.day, dt.year % 100)
This prints "1/25/13".
EDIT: This may not work on every platform:
datetime.datetime.strptime("2013-1-25", '%Y-%m-%d').strftime('%m/%d/%y')
If you can live with 01 for January instead of 1, then try…
d = datetime.datetime.strptime("2013-1-25", '%Y-%m-%d')
print datetime.date.strftime(d, "%m/%d/%y")
You can check the docs for other formatting directives.
I need to convert date string “2013-1-25” to string “1/25/13” in python.
I looked at the datetime.strptime but still can’t find a way for this.
I assume I have import datetime before running each of the lines of code below
datetime.datetime.strptime("2013-1-25", '%Y-%m-%d').strftime('%m/%d/%y')
prints "01/25/13".
If you can’t live with the leading zero, try this:
dt = datetime.datetime.strptime("2013-1-25", '%Y-%m-%d')
print '{0}/{1}/{2:02}'.format(dt.month, dt.day, dt.year % 100)
This prints "1/25/13".
EDIT: This may not work on every platform:
datetime.datetime.strptime("2013-1-25", '%Y-%m-%d').strftime('%m/%d/%y')
If you can live with 01 for January instead of 1, then try…
d = datetime.datetime.strptime("2013-1-25", '%Y-%m-%d')
print datetime.date.strftime(d, "%m/%d/%y")
You can check the docs for other formatting directives.