# How to sort the letters in a string alphabetically in Python

## Question:

Is there an easy way to sort the letters in a string alphabetically in Python?

So for:

``````a = 'ZENOVW'
``````

I would like to return:

``````'ENOVWZ'
``````

You can do:

``````>>> a = 'ZENOVW'
>>> ''.join(sorted(a))
'ENOVWZ'
``````
``````>>> a = 'ZENOVW'
>>> b = sorted(a)
>>> print b
['E', 'N', 'O', 'V', 'W', 'Z']
``````

`sorted` returns a list, so you can make it a string again using `join`:

``````>>> c = ''.join(b)
``````

which joins the items of `b` together with an empty string `''` in between each item.

``````>>> print c
'ENOVWZ'
``````

Sorted() solution can give you some unexpected results with other strings.

List of other solutions:

## Sort letters and make them distinct:

``````>>> s = "Bubble Bobble"
>>> ''.join(sorted(set(s.lower())))
' belou'
``````

## Sort letters and make them distinct while keeping caps:

``````>>> s = "Bubble Bobble"
>>> ''.join(sorted(set(s)))
' Bbelou'
``````

## Sort letters and keep duplicates:

``````>>> s = "Bubble Bobble"
>>> ''.join(sorted(s))
' BBbbbbeellou'
``````

If you want to get rid of the space in the result, add strip() function in any of those mentioned cases:

``````>>> s = "Bubble Bobble"
>>> ''.join(sorted(set(s.lower()))).strip()
'belou'
``````

You can use reduce

``````>>> a = 'ZENOVW'
>>> reduce(lambda x,y: x+y, sorted(a))
'ENOVWZ'
``````

the code can be used to sort string in alphabetical order without using any inbuilt function of python

k = input(“Enter any string again “)

``````li = []
x = len(k)
for i in range (0,x):
li.append(k[i])

print("List is : ",li)

for i in range(0,x):
for j in range(0,x):
if li[i]<li[j]:
temp = li[i]
li[i]=li[j]
li[j]=temp
j=""

for i in range(0,x):
j = j+li[i]

print("After sorting String is : ",j)
``````

Really liked the answer with the reduce() function. Here’s another way to sort the string using accumulate().

``````from itertools import accumulate
s = 'mississippi'
print(tuple(accumulate(sorted(s)))[-1])
``````

sorted(s) -> [‘i’, ‘i’, ‘i’, ‘i’, ‘m’, ‘p’, ‘p’, ‘s’, ‘s’, ‘s’, ‘s’]

tuple(accumulate(sorted(s)) -> (‘i’, ‘ii’, ‘iii’, ‘iiii’, ‘iiiim’, ‘iiiimp’, ‘iiiimpp’, ‘iiiimpps’, ‘iiiimppss’, ‘iiiimppsss’, ‘iiiimppssss’)

We are selecting the last index (-1) of the tuple

Python function`sorted` returns ASCII based result for string.

INCORRECT: In the example below, `e` and `d` is behind `H` and `W` due it’s to ASCII value.

``````>>>a = "Hello World!"
>>>"".join(sorted(a))
' !!HWdellloor'
``````

CORRECT: In order to write the sorted string without changing the case of letter. Use the code:

``````>>> a = "Hello World!"
>>> "".join(sorted(a,key=lambda x:x.lower()))
' !deHllloorW'

OR (Ref: https://docs.python.org/3/library/functions.html#sorted)

>>> a = "Hello World!"
>>> "".join(sorted(a,key=str.lower))
' !deHllloorW'
``````

If you want to remove all punctuation and numbers.
Use the code:

``````>>> a = "Hello World!"
>>> "".join(filter(lambda x:x.isalpha(), sorted(a,key=lambda x:x.lower())))
'deHllloorW'
``````
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