How to print a list in Python "nicely"

Question:

In PHP, I can do this:

echo '<pre>'
print_r($array);
echo '</pre>'

In Python, I currently just do this:

print the_list

However, this will cause a big jumbo of data. Is there any way to print it nicely into a readable tree? (with indents)?

Asked By: TIMEX

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Answers:

from pprint import pprint
pprint(the_list)
Answered By: John La Rooy

You mean something like…:

>>> print L
['this', 'is', 'a', ['and', 'a', 'sublist', 'too'], 'list', 'including', 'many', 'words', 'in', 'it']
>>> import pprint
>>> pprint.pprint(L)
['this',
 'is',
 'a',
 ['and', 'a', 'sublist', 'too'],
 'list',
 'including',
 'many',
 'words',
 'in',
 'it']
>>> 

…? From your cursory description, standard library module pprint is the first thing that comes to mind; however, if you can describe example inputs and outputs (so that one doesn’t have to learn PHP in order to help you;-), it may be possible for us to offer more specific help!

Answered By: Alex Martelli

A quick hack while debugging that works without having to import pprint would be to join the list on 'n'.

>>> lst = ['foo', 'bar', 'spam', 'egg']
>>> print 'n'.join(lst)
foo
bar
spam
egg
Answered By: shxfee

https://docs.python.org/3/library/pprint.html

If you need the text (for using with curses for example):

import pprint

myObject = []

myText = pprint.pformat(myObject)

Then myText variable will something alike php var_dump or print_r. Check the documentation for more options, arguments.

Answered By: Iacchus

Simply by “unpacking” the list in the print function argument and using a newline (n) as separator.

print(*lst, sep=’n’)

lst = ['foo', 'bar', 'spam', 'egg']
print(*lst, sep='n')

foo
bar
spam
egg
Answered By: MarcoP

As the other answers suggest pprint module does the trick.
Nonetheless, in case of debugging where you might need to put the entire list into some log file, one might have to use pformat method along with module logging along with pprint.

import logging
from pprint import pformat

logger = logging.getLogger('newlogger')
handler = logging.FileHandler('newlogger.log')

formatter = logging.Formatter('%(asctime)s %(levelname)s %(message)s')
handler.setFormatter(formatter)

logger.addHandler(handler) 
logger.setLevel(logging.WARNING)

data = [ (i, { '1':'one',
           '2':'two',
           '3':'three',
           '4':'four',
           '5':'five',
           '6':'six',
           '7':'seven',
           '8':'eight',
           })
         for i in xrange(3)
      ]

logger.error(pformat(data))

And if you need to directly log it to a File, one would have to specify an output stream, using the stream keyword. Ref

from pprint import pprint

with open('output.txt', 'wt') as out:
   pprint(myTree, stream=out)

See Stefano Sanfilippo’s answer

Answered By: El_Diablo

As other answers have mentioned, pprint is a great module that will do what you want. However if you don’t want to import it and just want to print debugging output during development, you can approximate its output.

Some of the other answers work fine for strings, but if you try them with a class object it will give you the error TypeError: sequence item 0: expected string, instance found.

For more complex objects, make sure the class has a __repr__ method that prints the property information you want:

class Foo(object):
    def __init__(self, bar):
        self.bar = bar

    def __repr__(self):
        return "Foo - (%r)" % self.bar

And then when you want to print the output, simply map your list to the str function like this:

l = [Foo(10), Foo(20), Foo("A string"), Foo(2.4)]
print "[%s]" % ",n ".join(map(str,l))

outputs:

 [Foo - (10),
  Foo - (20),
  Foo - ('A string'),
  Foo - (2.4)]

You can also do things like override the __repr__ method of list to get a form of nested pretty printing:

class my_list(list):
    def __repr__(self):
        return "[%s]" % ",n ".join(map(str, self))

a = my_list(["first", 2, my_list(["another", "list", "here"]), "last"])
print a

gives

[first,
 2,
 [another,
 list,
 here],
 last]

Unfortunately no second-level indentation but for a quick debug it can be useful.

Answered By: Aaron D

For Python 3, I do the same kind of thing as shxfee’s answer:

def print_list(my_list):
    print('n'.join(my_list))

a = ['foo', 'bar', 'baz']
print_list(a)

which outputs

foo
bar
baz

As an aside, I use a similar helper function to quickly see columns in a pandas DataFrame

def print_cols(df):
    print('n'.join(df.columns))
Answered By: aaronpenne
import json
some_list = ['one', 'two', 'three', 'four']
print(json.dumps(some_list, indent=4))

Output:

[
    "one",
    "two",
    "three",
    "four"
]
Answered By: Eyal Levin

you can also loop trough your list:

def fun():
  for i in x:
    print(i)

x = ["1",1,"a",8]
fun()
Answered By: vijay

This is a method from raw python that I use very often!

The code looks like this:

list = ["a", "b", "c", "d", "e", "f", "g"]

for i in range(len(list)):
    print(list[i])

output:

a
b
c
d
e
f
g
Answered By: Sixten Bohman
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