Adding Macros to Python

Question:

I would like to invoke the following code in-situ wherever I refer to MY_MACRO in my code below.

# MY_MACRO
frameinfo = getframeinfo(currentframe())
msg = 'We are on file ' + frameinfo.filename + ' and line ' +  str(frameinfo.lineno)
# Assumes access to namespace and the variables in which `MY_MACRO` is called. 
current_state = locals().items()

Here is some code that would use MY_MACRO:

def some_function:
    MY_MACRO

def some_other_function:
    some_function()
    MY_MACRO

class some_class:
  def some_method:
     MY_MACRO

In case it helps:

  1. One of the reasons why I would like to have this ability is because I would like to avoid repeating the code of MY_MACRO wherever I need it. Having something short and easy would be very helpful.
  2. Another reason is because I want to embed an IPython shell wihthin the macro and I would like to have access to all variables in locals().items() (see this other question)

Is this at all possible in Python? What would be the easiest way to get this to work?

Please NOTE that the macro assumes access to the entire namespace of the scope in which it’s called (i.e. merely placing the code MY_MACRO in a function would not work). Note also that if I place MY_MACRO in a function, lineno would output the wrong line number.

Answers:

How about a function you can call? This function accesses the caller’s frame, and rather than using locals(), uses frame.f_locals to get the caller’s namespace.

def my_function():
    frame = currentframe().f_back
    msg = 'We are on file {0.f_code.co_filename} and line {0.f_lineno}'.format(frame)
    current_state = frame.f_locals
    print current_state['some_variable']

Then just call it:

def some_function:
    my_function()

def some_other_function:
    some_function()
    my_function()

class some_class:
  def some_method:
     my_function()
Answered By: Ned Batchelder

you could use function if you wanted to:

def MY_MACRO():
    frame = currentframe()
    try:
        macro_caller_locals = frame.f_back.f_locals
        print(macro_caller_locals['a'])

    finally:
        del frame

def some_function:
    a = 1
    MY_MACRO()
Answered By: Serdalis

I’d say you should define a function to do this, since there are no macros in Python. It looks like you want to capture the current stack frame, which you could do simplify by passing in currentframe() from the call site to your shared function. Ditto with locals.

def print_frame_info(frameinfo, locals):
    msg = 'We are on file ' + frameinfo.filename + ' and line ' +  str(frameinfo.lineno)
    current_state = locals.items()

def some_other_function:
    some_function()
    print_frame_info(currentframe(), locals())
Answered By: tom

I’m not sure if this is a good solution, but it’s at least worth considering a macro preprocessor.

There are a few different extend-Python-with-macros projects, or wider projects that should make such a thing easier to do, but I only have expired links for all of them (Logix, MetaPython, Mython, Espy)… It might be worth looking for current links and/or newer/liver projects.

You can use something like m4 or cpp, or something more powerful, or even build one yourself. But really, you’ve just got a small, static set (so far, one) of purely textual macros. At worst you have to detect the indentation level of MY_MACRO and add that to the start of each line, which is trivial to do in a regex. Meaning sed, or a 3-liner Python script, can be your preprocessor.

However, there are two problems, or at least annoyances.

First, you need to preprocess your files. If you’re already using C extension modules or generated code or any other code that needs you to setup.py (or make or scons or whatever) before you can run it, or you’re using an IDE where you just hit cmd-R or ctrl-shift-B or whatever to test your code, this isn’t a problem. But for the typical edit-test loop with a text editor in one window and an interactive interpreter in another… well, you’ve just turned it into an edit-compile-test loop. Ugh. The only solution I can think of is an import hook that preprocesses every file before importing it as a module, which seems like a lot of work for a small benefit.

Second, your line numbers and source (from MY_MACRO itself, as well as from tracebacks and inspect.getsource and so on) are going to be the line numbers of the preprocessed files, not the original source that you have open for editing. Since your preprocessed files are pretty readable, that isn’t terrible (not as bad as coding CoffeeScript and debugging it as JavaScript, which most of the CoffeeScript community does every day…), but it’s definitely an annoyance.

Of course one way to solve this is to build your own macro processor into the interpreter, at whichever stage in the parse/compile process you want. I’m guessing that’s a whole lot more work than you want to do, but if you do, well, Guido always prefers to have an actual working design and implementation to reject instead of having to keep rejecting vague suggestions of “Hey, let’s add macros to Python”. 🙂

Answered By: abarnert

MacroPy is a project of mine which brings syntactic macros to Python. The project is only 3 weeks old, but if you look at the link, you’ll see we have a pretty cool collection of demos, and the functionality you want can definitely be implemented using it.

On the other hand, python has some pretty amazing introspection capabilities, so I suspect you may be able to accomplish what you want purely using that functionality.

Answered By: Li Haoyi

The use of exec is frowned upon, but it ought to do the trick here. For example, take the following macro:

MY_MACRO = """
print foo            
"""

and run it by using the following code:

foo = "breaking the rules"
exec MY_MACRO in globals(),locals() 

Always be careful with exec, because it can have strange side-effects and opens up opportunities for code injection.

Answered By: Dan

If you need only line and function name of caller like I needed for debug, you can get caller function information by inspect.getouterframes link.

import inspect
def printDebugInfo():
  (frame,filename,line_number,function_name, lines, 
    index) = inspect.getouterframes(inspect.currentframe())[1]
  print(filename, line_number, function_name, lines, index)

def f1():
  printDebugInfo()

if __name__=='__main__':
  f1()
Answered By: Ahmad Yoosofan
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