Keep duplicates in a list in Python

Question

I know this is probably an easy answer but I can’t figure it out. What is the best way in Python to keep the duplicates in a list:

x = [1,2,2,2,3,4,5,6,6,7]

The output should be:

[2,6]

I found this link: Find (and keep) duplicates of sublist in python, but I’m still relatively new to Python and I can’t get it to work for a simple list.

Asked By: myname

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Source

Answer 1

This is a short way to do it if the list is sorted already:

x = [1,2,2,2,3,4,5,6,6,7]

from itertools import groupby
print [key for key,group in groupby(x) if len(list(group)) > 1]

Answered By: Jochen Ritzel

Answer 2

I’d use a collections.Counter:

from collections import Counter
x = [1, 2, 2, 2, 3, 4, 5, 6, 6, 7]
counts = Counter(x)
output = [value for value, count in counts.items() if count > 1]

Here’s another version which keeps the order of when the item was first duplicated that only assumes that the sequence passed in contains hashable items and it will work back to when set or yeild was introduced to the language (whenever that was).

def keep_dupes(iterable):
    seen = set()
    dupes = set()
    for x in iterable:
        if x in seen and x not in dupes:
            yield x
            dupes.add(x)
        else:
            seen.add(x)

print list(keep_dupes([1,2,2,2,3,4,5,6,6,7]))

Answered By: mgilson

Answer 3

keepin’ it simple:

array2 = []
aux = 0
aux2=0
for i in x:
    aux2 = i
    if(aux2==aux):
        array2.append(i)
    aux= i
list(set(array2))

That should work

Answered By: luchosrock

Answer 4

Not efficient but just to get the output, you could try:

import numpy as np

def check_for_repeat(check_list):
    repeated_list = []

    for idx in range(len(check_list)):
        elem = check_list[idx]
        check_list[idx] = None

        if elem in temp_list:
            repeated_list.append(elem)

    repeated_list = np.array(repeated_list)

    return list(np.unique(repeated_list))

Answered By: L Ken

Answer 5

List Comprehension in combination with set() will do exactly what you want.

list(set([i for i in x if x.count(i) >= 2]))

>>> [2,6]

Answered By: Ivan

Keep duplicates in a list in Python

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