In python selenium, how does one find the visibility of an element?

Question

I found the is_visible method in the Selenium documentation, but I have no idea how to use it. I keep getting errors such as is_visible needs a selenium instance as the first parameter.

Also, what is a “locator”?

Any help would be appreciated.

Asked By: user2183536

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Source

Answer 1

You should use is_displayed() instead:

from selenium import webdriver

driver = webdriver.Firefox()
driver.get('http://www.google.com')
element = driver.find_element_by_id('gbqfba') #this element is visible
if element.is_displayed():
  print "Element found"
else:
  print "Element not found"

hidden_element = driver.find_element_by_name('oq') #this one is not
if hidden_element.is_displayed():
  print "Element found"
else:
  print "Element not found"

Answered By: rcdsystems

Answer 2

From here: https://www.selenium.dev/selenium/docs/api/py/webdriver_support/selenium.webdriver.support.expected_conditions.html

Just use

selenium.webdriver.support.expected_conditions.visibility_of

cos

Visibility means that the element is not only displayed but also has a
height and width that is greater than 0

Answered By: Zhivko.Kostadinov

In python selenium, how does one find the visibility of an element?

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