Writing a loop with a step size 10, to print out all 2-digit numbers ending in 7 in increasing order in python
Question:
Write a program, using a for loop with step size 10, to print out all 2-digit numbers which end in 7, in increasing order
I have no idea where to start, or how to do this. help please!
Answers:
range(stop)
range(start, stop[, step])
>>> for n in range(17, 100, 10):
print n
17
27
37
47
57
67
77
87
97
Write a program, using a for loop with step size 10, to print out all 2-digit numbers which end in 7, in increasing order
I have no idea where to start, or how to do this. help please!
range(stop)
range(start, stop[, step])
>>> for n in range(17, 100, 10):
print n
17
27
37
47
57
67
77
87
97