Clone an image in cv2 Python

Question

I’m new to OpenCV. What is the Python function which act the same as cv::clone() in C++?

I just try to get a rect by

    rectImg = img[10:20, 10:20]

but when I draw a line on it, I find the line appear both on img and the rectImage, so, how can I get this done?

Asked By: tintin

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Source

Answer 1

If you use cv2, the correct method is to use the .copy() method in NumPy. It will create a copy of the array you need. Otherwise it will produce only a view of that object.

For example:

In [1]: import numpy as np

In [2]: x = np.arange(10*10).reshape((10, 10))

In [4]: y = x[3:7, 3:7].copy()

In [6]: y[2, 2] = 1000

In [8]: 1000 in x
Out[8]: False     # See, 1000 in y doesn't change values in x, the parent array.

Answered By: Abid Rahman K

Answer 2

You can simply use the Python standard library. Make a shallow copy of the original image as follows:

import copy

original_img = cv2.imread("foo.jpg")
clone_img = copy.copy(original_img)

Answered By: yildirim

Answer 3

My favorite method uses cv2.copyMakeBorder with no border, like so.

copy = cv2.copyMakeBorder(original,0,0,0,0,cv2.BORDER_REPLICATE)

Answered By: Jack Guy

Answer 4

Abid Rahman K’s answer is correct, but you say that you are using cv2 which inherently uses NumPy arrays. So, to make a complete different copy of say "myImage":

newImage = myImage.copy()

The above is enough. There isn’t any need to import NumPy (numpy).

Answered By: Ash Ketchum

Answer 5

Using Python 3 and opencv-python version 4.4.0, the following code should work:

img_src = cv2.imread('image.png')
img_clone = img_src.copy()

Answered By: Ashadi Sedana Pratama

Clone an image in cv2 Python

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