How to format raw string with different expressions inside?

Question

Let’s say, we want to catch something with regex, using rawstring to define the pattern, which pattern has repeating elements, and variables inside. And we also want to use the format() string formatting form. How to do this?

import re
text = '"""!some text'
re.findall(r'"{3}{symbol}somestext'.format(symbol='!'), text)

But this line leads us to an IndexError:

# IndexError: tuple index out of range

So, my question is: how to format a raw string if it has formatting curly-braces expression, and repeating curly-braces expression inside?

Thanks in advance!

Asked By: Peter Varo

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Source

Answer 1

Escape the curly brackets with curly brackets

>>> import re
>>> text = '"""!some text'
>>> re.findall(r'"{{3}}{symbol}somestext'.format(symbol='!'), text)
['"""!some text']

However it is better to just use % formatting in this situation.

Answered By: jamylak

Answer 2

Use f-strings (introduced in Python 3.6):

a = 15
print(fr'Escape is here:n but still {a}')

# => Escape is here:n but still 15

Answered By: Daniel Malachov

How to format raw string with different expressions inside?

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