iterating over two values of a list at a time in python

Question

I have a set like (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08) which I need to iterate over, like

    for x,y in (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
        print (x,y)

which would print

    669256.02 6117662.09
    669258.61 6117664.39
    669258.05 6117665.08

im on Python 3.3 btw

Asked By: Rasmus Damgaard Nielsen

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Source

Answer 1

You can use an iterator:

>>> lis = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> it = iter(lis)
>>> for x in it:
...     print (x, next(it))
...     
669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08

Answered By: Ashwini Chaudhary

Answer 2

>>> nums = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> for x, y in zip(*[iter(nums)]*2):
        print(x, y)


669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08

Answered By: jamylak

Answer 3

The grouper example in the itertools recipes section should help you here:
http://docs.python.org/library/itertools.html#itertools-recipes

from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
    "Collect data into fixed-length chunks or blocks"
    # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
    args = [iter(iterable)] * n
    return zip_longest(*args, fillvalue=fillvalue)

You would then it use like this:

for x, y in grouper(my_set, 2, 0.0):  # Use 0.0 to pad with a float
    print(x, y)

Answered By: Lllama

iterating over two values of a list at a time in python

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