Change image AND image position by using loops [python]

Question

I’m trying to print out images that correspond to a list of names.

I have the following code already:

for item in player_hand:
    screen.blit(pygame.image.load(os.path.join('Images',item.name+'.png')), (100, 100))

I want to update the tuple (100,100) so that each new image gets printed to the right of the previous image.

What’s the simplest way to accomplish this?

Asked By: bhamhawker

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Source

Answer 1

Use enumerate to introduce an increasing variable to the loop. For instance

for n, item in enumerate(player_hand):
    screen.blit(pygame.image.load(os.path.join('Images',item.name+'.png')), (100+n*10, 100))

Answered By: Milo Wielondek

Answer 2

like this?

count=0
for item in player_hand:
   screen.blit(pygame.image.load(os.path.join('Images',item.name+'.png')), (100+count, 100))
   count=count+distance

where distance is how much on the right you need it

this way is the best because you can change how much to move the image each time the loop is repeated by adding the value of an array! (e.g: if you need different distances or have imges of different size)

Answered By: Anze

Change image AND image position by using loops [python]

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